[sql] Select rows which are not present in other table

I've got two postgresql tables:

table name     column names
-----------    ------------------------
login_log      ip | etc.
ip_location    ip | location | hostname | etc.

I want to get every IP address from login_log which doesn't have a row in ip_location.
I tried this query but it throws a syntax error.

SELECT login_log.ip 
FROM login_log 
WHERE NOT EXIST (SELECT ip_location.ip
                 FROM ip_location
                 WHERE login_log.ip = ip_location.ip)

ERROR: syntax error at or near "SELECT"
LINE 3: WHERE NOT EXIST (SELECT ip_location.ip`

I'm also wondering if this query (with adjustments to make it work) is the best performing query for this purpose.

SELECT * FROM testcases1 t WHERE NOT EXISTS ( SELECT 1
FROM executions1 i WHERE t.tc_id = i.tc_id and t.pro_id=i.pro_id and pro_id=7 and version_id=5 ) and pro_id=7 ;

Here testcases1 table contains all datas and executions1 table contains some data among testcases1 table. I am retrieving only the datas which are not present in exections1 table. ( and even I am giving some conditions inside that you can also give.) specify condition which should not be there in retrieving data should be inside brackets.

A.) The command is NOT EXISTS, you're missing the 'S'.

B.) Use NOT IN instead

SELECT ip 
  FROM login_log 
  WHERE ip NOT IN (
    SELECT ip
    FROM ip_location
  )
;

this can also be tried...

SELECT l.ip, tbl2.ip as ip2, tbl2.hostname
FROM   login_log l 
LEFT   JOIN (SELECT ip_location.ip, ip_location.hostname
             FROM ip_location
             WHERE ip_location.ip is null)tbl2