I have been studying Python, and I read a chapter which describes the None
value, but unfortunately this book isn't very clear at some points. I thought that I would find the answer to my question, if I share it there.
I want to know what the None
value is and what do you use it for?
And also, I don't get this part of the book:
Assigning a value of
None
to a variable is one way to reset it to its original, empty state.
What does that mean?
The answers were great, although I didn't understand most of answers due to my low knowledge of the computer world (I haven't learned about classes, objects, etc.). What does this sentence mean?
Assigning a value of
None
to a variable is one way to reset it to its original, empty state.
Final:
Finally I've got my answer from looking to different answers. I must appreciate all the people who put their times to help me (especially Martijn Pieters and DSM), and I wish that I could choose all answers as the best, but the selection is limited to one. All of the answers were great.
This question is related to
python
variables
if-statement
largest=none
smallest =none
While True :
num =raw_input ('enter a number ')
if num =="done ": break
try :
inp =int (inp)
except:
Print'Invalid input'
if largest is none :
largest=inp
elif inp>largest:
largest =none
print 'maximum', largest
if smallest is none:
smallest =none
elif inp<smallest :
smallest =inp
print 'minimum', smallest
print 'maximum, minimum, largest, smallest
Other answers have already explained meaning of None beautifully. However, I would still like to throw more light on this using an example.
Example:
def extendList(val, list=[]):
list.append(val)
return list
list1 = extendList(10)
list2 = extendList(123,[])
list3 = extendList('a')
print "list1 = %s" % list1
print "list2 = %s" % list2
print "list3 = %s" % list3
Now try to guess output of above list. Well, the answer is surprisingly as below:
list1 = [10, 'a']
list2 = [123]
list3 = [10, 'a']
But Why?
Many will mistakenly expect list1 to be equal to [10] and list3 to be equal to ['a'], thinking that the list argument will be set to its default value of [] each time extendList is called.
However, what actually happens is that the new default list is created only once when the function is defined, and that same list is then used subsequently whenever extendList is invoked without a list argument being specified. This is because expressions in default arguments are calculated when the function is defined, not when it’s called.
list1 and list3 are therefore operating on the same default list, whereas list2 is operating on a separate list that it created (by passing its own empty list as the value for the list parameter).
'None' the savior: (Modify example above to produce desired behavior)
def extendList(val, list=None):
if list is None:
list = []
list.append(val)
return list
list1 = extendList(10)
list2 = extendList(123,[])
list3 = extendList('a')
print "list1 = %s" % list1
print "list2 = %s" % list2
print "list3 = %s" % list3
With this revised implementation, the output would be:
list1 = [10]
list2 = [123]
list3 = ['a']
Note - Example credit to toptal.com
None is a singleton object (meaning there is only one None), used in many places in the language and library to represent the absence of some other value.
For example:
if d
is a dictionary, d.get(k)
will return d[k]
if it exists, but None
if d
has no key k
.
Read this info from a great blog: http://python-history.blogspot.in/
All of these are good answers but I think there's more to explain why None
is useful.
Imagine you collecting RSVPs to a wedding. You want to record whether each person will attend. If they are attending, you set person.attending = True
. If they are not attending you set person.attending = False
. If you have not received any RSVP, then person.attending = None
. That way you can distinguish between no information - None
- and a negative answer.
This is what the Python documentation has got to say about None
:
The sole value of types.NoneType. None is frequently used to represent the absence of a value, as when default arguments are not passed to a function.
Changed in version 2.4: Assignments to None are illegal and raise a SyntaxError.
Note The names None and debug cannot be reassigned (assignments to them, even as an attribute name, raise SyntaxError), so they can be considered “true” constants.
Let's confirm the type of None
first
print type(None)
print None.__class__
Output
<type 'NoneType'>
<type 'NoneType'>
Basically, NoneType
is a data type just like int
, float
, etc. You can check out the list of default types available in Python in 8.15. types — Names for built-in types.
And, None
is an instance of NoneType
class. So we might want to create instances of None
ourselves. Let's try that
print types.IntType()
print types.NoneType()
Output
0
TypeError: cannot create 'NoneType' instances
So clearly, cannot create NoneType
instances. We don't have to worry about the uniqueness of the value None
.
Let's check how we have implemented None
internally.
print dir(None)
Output
['__class__', '__delattr__', '__doc__', '__format__', '__getattribute__',
'__hash__', '__init__', '__new__', '__reduce__', '__reduce_ex__',
'__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__']
Except __setattr__
, all others are read-only attributes. So, there is no way we can alter the attributes of None
.
Let's try and add new attributes to None
setattr(types.NoneType, 'somefield', 'somevalue')
setattr(None, 'somefield', 'somevalue')
None.somefield = 'somevalue'
Output
TypeError: can't set attributes of built-in/extension type 'NoneType'
AttributeError: 'NoneType' object has no attribute 'somefield'
AttributeError: 'NoneType' object has no attribute 'somefield'
The above seen statements produce these error messages, respectively. It means that, we cannot create attributes dynamically on a None
instance.
Let us check what happens when we assign something None
. As per the documentation, it should throw a SyntaxError
. It means, if we assign something to None
, the program will not be executed at all.
None = 1
Output
SyntaxError: cannot assign to None
We have established that
None
is an instance of NoneType
None
cannot have new attributesNone
cannot be changed.NoneType
None
by assigning values to it.So, as mentioned in the documentation, None
can really be considered as a true constant
.
Happy knowing None
:)
I love code examples (as well as fruit), so let me show you
apple = "apple"
print(apple)
>>> apple
apple = None
print(apple)
>>> None
None means nothing, it has no value.
None evaluates to False.
None
is just a value that commonly is used to signify 'empty', or 'no value here'. It is a signal object; it only has meaning because the Python documentation says it has that meaning.
There is only one copy of that object in a given Python interpreter session.
If you write a function, and that function doesn't use an explicit return
statement, None
is returned instead, for example. That way, programming with functions is much simplified; a function always returns something, even if it is only that one None
object.
You can test for it explicitly:
if foo is None:
# foo is set to None
if bar is not None:
# bar is set to something *other* than None
Another use is to give optional parameters to functions an 'empty' default:
def spam(foo=None):
if foo is not None:
# foo was specified, do something clever!
The function spam()
has a optional argument; if you call spam()
without specifying it, the default value None
is given to it, making it easy to detect if the function was called with an argument or not.
Other languages have similar concepts. SQL has NULL
; JavaScript has undefined
and null
, etc.
Note that in Python, variables exist by virtue of being used. You don't need to declare a variable first, so there are no really empty variables in Python. Setting a variable to None
is then not the same thing as setting it to a default empty value; None
is a value too, albeit one that is often used to signal emptyness. The book you are reading is misleading on that point.
The book you refer to is clearly trying to greatly simplify the meaning of None
. Python variables don't have an initial, empty state – Python variables are bound (only) when they're defined. You can't create a Python variable without giving it a value.
>>> print(x)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'x' is not defined
>>> def test(x):
... print(x)
...
>>> test()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: test() takes exactly 1 argument (0 given)
>>> def test():
... print(x)
...
>>> test()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 2, in test
NameError: global name 'x' is not defined
but sometimes you want to make a function mean different things depending on whether a variable is defined or not. You can create an argument with a default value of None
:
>>> def test(x=None):
... if x is None:
... print('no x here')
... else:
... print(x)
...
>>> test()
no x here
>>> test('x!')
x!
The fact that this value is the special None
value is not terribly important in this case. I could've used any default value:
>>> def test(x=-1):
... if x == -1:
... print('no x here')
... else:
... print(x)
...
>>> test()
no x here
>>> test('x!')
x!
…but having None
around gives us two benefits:
-1
whose meaning is unclear, and-1
as a normal input.>>> test(-1)
no x here
oops!
So the book is a little misleading mostly in its use of the word reset – assigning None
to a name is a signal to a programmer that that value isn't being used or that the function should behave in some default way, but to reset a value to its original, undefined state you must use the del
keyword:
>>> x = 3
>>> x
3
>>> del x
>>> x
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'x' is not defined
Source: Stackoverflow.com