find -type f -exec chmod 644

Question

why doesn t this work I am trying to change all files to 644 abd all -d to 755   find   -type f -exec chmod 644        i get  find  missing argument to  -exec   thanks

User · Answer

Piping to xargs is a dirty way of doing that which can be done inside of find.

find . -type d -exec chmod 0755 {} \;
find . -type f -exec chmod 0644 {} \;

You can be even more controlling with other options, such as:

find . -type d -user harry -exec chown daisy {} \;

You can do some very cool things with find and you can do some very dangerous things too. Have a look at "man find", it's long but is worth a quick read. And, as always remember:

If you are root it will succeed.
If you are in root (/) you are going to have a bad day.
Using /path/to/directory can make things a lot safer as you are clearly defining where you want find to run.

User · Answer

I need this so often that I created a function in my    bashrc file   chmodf             find  2 -type f -exec chmod  1         chmodd             find  2 -type d -exec chmod  1           Now I can use these shortcuts   chmodd 0775   chmodf 0664

User · Answer

A good alternative is this   find   -type f   xargs chmod -v 644   and for directories   find   -type d   xargs chmod -v 755   and to be more explicit   find   -type f   xargs -I   chmod -v 644

[magento] find . -type f -exec chmod 644 {} ;

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