nodejs get file name from absolute path

Question

If there any API could retrieve file name from an absolute file path   e g   foo txt  from   var www foo txt   I know it works with string operation  like fullpath replace             but I want to know is there a more  formal  way  like file getName   in java  could do it   NodeJS get file name from absolute path

User · Answer

To get the file name portion of the file name, the basename method is used:

var path = require("path");
var fileName = "C:\\Python27\\ArcGIS10.2\\python.exe";
var file = path.basename(fileName);

console.log(file); // 'python.exe'

If you want the file name without the extension, you can pass the extension variable (containing the extension name) to the basename method telling Node to return only the name without the extension:

var path = require("path");
var fileName = "C:\\Python27\\ArcGIS10.2\\python.exe";
var extension = path.extname(fileName);
var file = path.basename(fileName,extension);

console.log(file); // 'python'

User · Answer

For those interested in removing extension from filename  you can use https   nodejs org api path html path path basename path ext  path basename   foo bar baz asdf quux html     html

User · Answer

Use the basename method of the path module   path basename   foo bar baz asdf quux html      returns  quux html    Here is the documentation the above example is taken from

User · Answer

So Nodejs comes with the default global variable called     fileName  that holds the current file being executed My advice is to pass the   fileName to a service from any file   so that the retrieval of the fileName is made dynamic  Below  I make use of the fileName string and then split it based on the path sep  Note path sep avoids issues with posix file seperators and windows file seperators  issues with      and       It is much cleaner  Getting the substring and getting only the last seperated name and subtracting it with the actulal length by 3 speaks for itself   You can write a service like this  Note this is in typescript   but you can very well write it in js    export class AppLoggingConstants        constructor                    Here make sure the fileName param is actually    fileName      getDefaultMedata fileName  string  methodName  string            const appName   APP NAME          const actualFileName   fileName substring fileName lastIndexOf path sep  1  fileName length - 3             const actualFileName   fileName       return appName    --   actualFileName             export const AppLoggingConstantsInstance   new AppLoggingConstants

User · Answer

var path   require  quot path quot    var filepath    quot C   Python27  ArcGIS10 2  python exe quot   var name   path parse filepath  name     returns  python   Above code returns the name of the file without extension  if you need the name with extention use var path   require  quot path quot    var filepath    quot C   Python27  ArcGIS10 2  python exe quot   var name   path basename filepath      returns  python exe

User · Answer

If you already know that the path separator is    i e  you are writing for a specific platform environment   as implied by the example in your question  you could keep it simple and split the string by separator     foo bar baz asdf quux html  split      pop     That would be faster  and cleaner imo  than replacing by regular expression   Again  Only do this if you re writing for a specific environment  otherwise use the path module  as paths are surprisingly complex  Windows  for instance  supports   in many cases but not for e g  the       style prefixes used for shared network folders and the like  On Windows the above method is doomed to fail  sooner or later

User · Answer

In NodeJS    filename split        pop   returns just the file name from the absolute file path on any OS platform  Why need to care about remembering importing an API while this regex approach also letting us recollect our regex skills

[node.js] nodejs get file name from absolute path?

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