Current Codes:
<?php
// See the AND operator; How do I simplify/shorten this line?
if( $some_variable !== 'uk' && $some_variable !== 'in' ) {
// Do something
}
?>
And:
<?php
// See the OR operator; How do I simplify/shorten this line?
if( $some_variable !== 'uk' || $some_variable !== 'in' ) {
// Do something else
}
?>
Is there a simpler (i.e. shorter) way to write the two conditions?
NOTE: Yes, they are different, and I am expecting different ways to shorten the codes.
This question is related to
php
if-statement
conditional-statements
If you're planning on building a function in the if statement, I'd also advise the use of in_array. It's a lot cleaner.
If you're attempting to assign values to variables you can use the if/else shorthand:
$variable_to_fill = $some_variable !== 'uk' ? false : true;
You can make use of in_array()
in PHP.
$os = array("uk", "us"); // You can set multiple check conditions here
if (in_array("uk", $os)) //Founds a match !
{
echo "Got you";
}
An alternative that might make sense especially if this test is being made multiple times and you are running PHP 7+ and have installed the Set
class is:
use Ds\Set;
$strings = new Set(['uk', 'in']);
if (!$strings->contains($some_variable)) {
Or on any version of PHP you can use an associative array to simulate a set:
$strings = ['uk' => 1, 'in' => 1];
if (!isset($strings[$some_variable])) {
There is additional overhead in creating the set but each test then becomes an O(1) operation. Of course the savings becomes greater the longer the list of strings being compared is.
You may find it more readable to reverse your logic and use an else statement with an empty if.
if($some_variable === 'uk' || $another_variable === 'in'){}
else {
// This occurs when neither of the above are true
}
Some basic regex would do the trick nicely for $some_variable !== 'uk' && $some_variable !== 'in':
if(!preg_match('/^uk|in$/', $some_variable)) {
// Do something
}
You need to multi value check. Try using the following code :
<?php
$illstack=array(...............);
$val=array('uk','bn','in');
if(count(array_intersect($illstack,$val))===count($val)){ // all of $val is in $illstack}
?>
Source: Stackoverflow.com