Check if all values in list are greater than a certain number

Question

my list1    30 34 56  my list2    29 500 43    How to I check if all values in list are    30  my list1 should work and my list2 should not   The only thing I could think of doing was   boolean   0 def func ls       for k in ls          if k  gt   30              boolean   boolean   1         else              boolean   0     if boolean  gt  0          print  Continue      elif boolean   0          pass   Update 2016   In hindsight  after dealing with bigger datasets where speed actually matters and utilizing numpy   I would do this    gt  gt  gt  my list1    30 34 56   gt  gt  gt  my list2    29 500 43    gt  gt  gt  import numpy as np  gt  gt  gt  A 1   np array my list1   gt  gt  gt  A 2   np array my list2    gt  gt  gt  A 1  gt   30 array   True   True   True   dtype bool   gt  gt  gt  A 2  gt   30 array  False   True   True   dtype bool    gt  gt  gt    A 1  gt   30  sum      A 1 size  astype np int  1  gt  gt  gt    A 2  gt   30  sum      A 2 size  astype np int  0   You could also do something like    len   filter lambda x  x  gt   30  my list1     gt  0

User · Answer

I write this function  def larger x  than 0       if not x or min x   gt  than          return True     return False   Then  print larger  5  6  7   than 5     False print larger  6  7  8   than 5     True print larger     than 5     True print larger  6  7  8  None   than 5     False     Empty list on min   will raise ValueError  So I added if not x in condition

User · Answer

There is a builtin function all   all  x  gt  limit for x in my list    Being limit the value greater than which all numbers must be

User · Answer

You can use all     my list1    30 34 56  my list2    29 500 43  if all i  gt   30 for i in my list1       print  yes  if all i  gt   30 for i in my list2       print  no    Note that this includes all numbers equal to 30 or higher  not strictly above 30

User · Answer

a     a  2    b  3    c  4    d  5    a  1    b  6    e  7    h  8    I need this from above one  a     a  3    b  9    c  4    d  5    e  7    h  8    a append  0  0   for i in range len a         for j in range i   1  len a  - 1               if a i  0     a j  0                       a i  1     a j  1                      del a j  a pop

User · Answer

Use the all   function with a generator expression    gt  gt  gt  my list1    30  34  56   gt  gt  gt  my list2    29  500  43   gt  gt  gt  all i  gt   30 for i in my list1  True  gt  gt  gt  all i  gt   30 for i in my list2  False   Note that this tests for greater than or equal to 30  otherwise my list1 would not pass the test either   If you wanted to do this in a function  you d use   def all 30 or up ls       for i in ls          if i  lt  30              return False     return True   e g  as soon as you find a value that proves that there is a value below 30  you return False  and return True if you found no evidence to the contrary   Similarly  you can use the any   function to test if at least 1 value matches the condition

User · Answer

You could do the following   def Lists         my list1    30 34 56      my list2    29 500 43       for element in my list1          print element  gt   30       for element in my list2          print element  gt   30   Lists     This will return the values that are greater than 30 as True  and the values that are smaller as false

User · Answer

The overall winner between using the np sum  np min  and all seems to be np min in terms of speed for large arrays   N   1000000 def func sum x       my list   np random randn N      return np sum my list  lt  x    0  def func min x       my list   np random randn N      return np min my list   gt   x  def func all x       my list   np random randn N      return all i  gt   x for i in my list     i need to put the np array definition inside the function  otherwise the np min function remembers the value and does not do the computation again when testing for speed with timeit   The performance of  all  depends very much on when the first element that does not satisfy the criteria is found  the np sum needs to do a bit of operations  the np min is the lightest in terms of computations in the general case   When the criteria is almost immediately met and the all loop exits fast  the all function is winning just slightly over np min    gt  gt  gt   timeit func sum 10  10 loops  best of 3  36 1 ms per loop   gt  gt  gt   timeit func min 10  10 loops  best of 3  35 1 ms per loop   gt  gt  gt   timeit func all 10  10 loops  best of 3  35 ms per loop   But when  all  needs to go through all the points  it is definitely much worse  and the np min wins    gt  gt  gt   timeit func sum -10  10 loops  best of 3  36 2 ms per loop   gt  gt  gt   timeit func min -10  10 loops  best of 3  35 2 ms per loop   gt  gt  gt   timeit func all -10  10 loops  best of 3  230 ms per loop   But using  np sum my list lt x    can be very useful is one wants to know how many values are below x

User · Answer

any reason why you can t use min     def above my list  minimum       if min my list   gt   minimum          print  All values are equal or above   minimum     else          print  Not all values are equal or above   minimum   I don t know if this is exactly what you want  but technically  this is what you asked for

[python] Check if all values in list are greater than a certain number

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