[python] 'list' object has no attribute 'shape'

how to create an array to numpy array?

def test(X, N):
    [n,T] = X.shape
    print "n : ", n
    print "T : ", T



if __name__=="__main__":

    X = [[[-9.035250067710876], [7.453250169754028], [33.34074878692627]], [[-6.63700008392334], [5.132999956607819], [31.66075038909912]], [[-5.1272499561309814], [8.251499891281128], [30.925999641418457]]]
    N = 200
    test(X, N)

I am getting error as

AttributeError: 'list' object has no attribute 'shape'

So, I think I need to convert my X to numpy array?

list object in python does not have 'shape' attribute because 'shape' implies that all the columns (or rows) have equal length along certain dimension.

Let's say list variable a has following properties: a = [[2, 3, 4] [0, 1] [87, 8, 1]]

it is impossible to define 'shape' for variable 'a'. That is why 'shape' might be determined only with 'arrays' e.g.

b = numpy.array([[2, 3, 4]
                [0, 1, 22]
                [87, 8, 1]])

I hope this explanation clarifies well this question.

import numpy
X = numpy.array(the_big_nested_list_you_had)

It's still not going to do what you want; you have more bugs, like trying to unpack a 3-dimensional shape into two target variables in test.

If you have list, you can print its shape as if it is converted to array

import numpy as np
print(np.asarray(X).shape)

firstly u have to import numpy library (refer code for making a numpy array) shape only gives the output only if the variable is attribute of numpy library .in other words it must be a np.array or any other data structure of numpy. Eg.

`>>> import numpy
>>> a=numpy.array([[1,1],[1,1]])
>>> a.shape
(2, 2)`

if the type is list, use len(list) and len(list[0]) to get the row and column.

l = [[1,2,3,4], [0,1,3,4]]

len(l) will be 2 len(l[0]) will be 4

Alternatively, you can use np.shape(...)

For instance:

import numpy as np

a=[1,2,3]

and np.shape(a) will give an output of (3,)