[java] Filter Java Stream to 1 and only 1 element

Update

Nice suggestion in comment from @Holger:

Optional<User> match = users.stream()
              .filter((user) -> user.getId() > 1)
              .reduce((u, v) -> { throw new IllegalStateException("More than one ID found") });

Original answer

The exception is thrown by Optional#get, but if you have more than one element that won't help. You could collect the users in a collection that only accepts one item, for example:

User match = users.stream().filter((user) -> user.getId() > 1)
                  .collect(toCollection(() -> new ArrayBlockingQueue<User>(1)))
                  .poll();

which throws a java.lang.IllegalStateException: Queue full, but that feels too hacky.

Or you could use a reduction combined with an optional:

User match = Optional.ofNullable(users.stream().filter((user) -> user.getId() > 1)
                .reduce(null, (u, v) -> {
                    if (u != null && v != null)
                        throw new IllegalStateException("More than one ID found");
                    else return u == null ? v : u;
                })).get();

The reduction essentially returns:

  • null if no user is found
  • the user if only one is found
  • throws an exception if more than one is found

The result is then wrapped in an optional.

But the simplest solution would probably be to just collect to a collection, check that its size is 1 and get the only element.

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