Prepare for Segue in Swift

Question

I m facing the error message    UIStoryboardSegue does not have a member named  identifier     Here s the code causing the error  if  segue identifier     Load View            pass data to next view     On Obj-C it s fine using like this   if   segue identifier isEqualToString   Load View            pass data to next view     What am I doing wrong

User · Answer

For Swift 2 3 swift3 and swift4   Create a perform Segue at didSelectRowAtindexPath  For Ex       self performSegue withIdentifier   uiView   sender  self    After that Create a prepareforSegue function to catch the Destination segue and pass the value   Ex     override func prepare for segue  UIStoryboardSegue  sender  Any             if segue identifier     uiView            let destView   segue destination as  WebViewController         let indexpath   self newsTableView indexPathForSelectedRow         let indexurl   tableDatalist  indexpath  row    link         destView UrlRec   indexurl            let url                  You need to create a variable named UrlRec in Destination ViewController

User · Answer

Change the segue identifier in the right panel in the section with an id  icon to match the string you used in your conditional

User · Answer

Swift 1 2      override func prepareForSegue segue  UIStoryboardSegue  sender  AnyObject                 if  segue identifier     ShowDeal                      if let viewController  DealLandingViewController   segue destinationViewController as  DealLandingViewController                       viewController dealEntry   deal

User · Answer

Provided you aren t using the same destination view controller with different identifiers  the code can be more concise than the other solutions  and avoids the as  in some of the other answers    override func prepare for segue  NSStoryboardSegue  sender  Any         if let myViewController   segue destinationController as  MyViewController               Set up the VC

User · Answer

this is one of the ways you can use this function  it is when you want access a variable of another class and change the output based on that variable      override func prepare for segue  UIStoryboardSegue  sender  Any              let something   segue destination as  someViewController        something aVariable   anotherVariable

User · Answer

Prepare for Segue in  Swift 4 2 and Swift 5       override func prepare for segue  UIStoryboardSegue  sender  Any         if  segue identifier     OrderVC                pass data to next view         let viewController   segue destination as  MyOrderDetailsVC         viewController  OrderData   self MyorderArray selectedIndex              How to Call  segue  On specific Event Like Button Click etc    performSegue withIdentifier   OrderVC   sender  self

User · Answer

Swift 4  Swift 3  override func prepare for segue  UIStoryboardSegue  sender  Any         if segue identifier     MySegueId            if let nextViewController   segue destination as  NextViewController                   nextViewController valueOfxyz    XYZ    Or pass any values                 nextViewController valueOf123   123

User · Answer

override func prepareForSegue segue  UIStoryboardSegue   sender  AnyObject             if segue  identifier               var name   segue  identifier              if  name compare  Load View      0                                    You can t compare the the identifier with    you have to use the compare   method

User · Answer

I think the problem is you have to use the   to unbundle identifier  I have  override func prepareForSegue segue  UIStoryboardSegue   sender  AnyObject             if segue  identifier     Details                let viewController ViewController   segue  destinationViewController as ViewController             let indexPath   self tableView indexPathForSelectedRow               viewController pinCode   self exams indexPath row                      My understanding is that without the   you just get a true or false value

User · Answer

This seems to be due to a problem in the UITableViewController subclass template  It comes with a version of the prepareForSegue method that would require you to unwrap the segue   Replace your current prepareForSegue function with   override func prepareForSegue segue  UIStoryboardSegue   sender  AnyObject         if  segue identifier     Load View                pass data to next view           This version implicitly unwraps the parameters  so you should be fine

[ios] Prepare for Segue in Swift

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