[c#] How to get file path from OpenFileDialog and FolderBrowserDialog?

Hey there i started learning C# a few days ago and I'm trying to make a program that copies and pastes files (and replaces if needed) to a selected directory but I don't know how to get the directory and file paths from the openfiledialog and folderbrowserdialog

what am I doing wrong?

Here's the code:

namespace filereplacer
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void direc_Click(object sender, EventArgs e)
        {
            string folderPath = "";
            FolderBrowserDialog directchoosedlg = new FolderBrowserDialog();
            if (directchoosedlg.ShowDialog() == DialogResult.OK)
            {
                folderPath = directchoosedlg.SelectedPath;
            }
        }

        private void choof_Click(object sender, EventArgs e)
        {

            OpenFileDialog choofdlog = new OpenFileDialog();
            choofdlog.Filter = "All Files (*.*)|*.*";
            choofdlog.FilterIndex = 1;

            choofdlog.Multiselect = true;
            choofdlog.ShowDialog();
        }

        private void replacebtn_Click(object sender, EventArgs e)
        {
          // This is where i'm having trouble
        }

        public static void ReplaceFile(string FileToMoveAndDelete, string FileToReplace, string BackupOfFileToReplace)
        {
            File.Replace(FileToMoveAndDelete, FileToReplace, BackupOfFileToReplace, false);
        }
    }

This question is related to c# openfiledialog folderbrowserdialog

The answer is


Use the Path class from System.IO. It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.

Usage is simple.

string directoryPath = System.IO.Path.GetDirectoryName(choofdlog.FileName);

Create this class as Extension:

public static class Extensiones
{
    public static string FolderName(this OpenFileDialog ofd)
    {
            string resp = "";
            resp = ofd.FileName.Substring(0, 3);
            var final = ofd.FileName.Substring(3);
            var info = final.Split('\\');
            for (int i = 0; i < info.Length - 1; i++)
            {
                resp += info[i] + "\\";
            }
            return resp;
    }
}

Then, you could use in this way:

        //ofdSource is an OpenFileDialog 
        if (ofdSource.ShowDialog(this) == DialogResult.OK)
        {
            MessageBox.Show(ofdSource.FolderName());
        }

you can store the Path into string variable like

string s = choofdlog.FileName;

I am sorry if i am late to reply here but i just thought i should throw in a much simpler solution for the OpenDialog.

OpenDialog ofd = new OpenDialog();
var fullPathIncludingFileName = ofd.Filename; //returns the full path including the filename
var fullPathExcludingFileName = ofd.Filename.Replace(ofd.SafeFileName, "");//will remove the filename from the full path

I have not yet used a FolderBrowserDialog before so i will trust my fellow coders's take on this. I hope this helps.


To get the full file path of a selected file or files, then you need to use FileName property for one file or FileNames property for multiple files.

var file = choofdlog.FileName; // for one file

or for multiple files

var files = choofdlog.FileNames; // for multiple files.

To get the directory of the file, you can use Path.GetDirectoryName
Here is Jon Keet's answer to a similar question about getting directories from path


Your choofdlog holds a FileName and FileNames (for multi-selection) containing the file paths, after the ShowDialog() returns.


A primitive quick fix that works.

If you only use OpenFileDialog, you can capture the FileName, SafeFileName, then subtract to get folder path:

exampleFileName = ofd.SafeFileName;
exampleFileNameFull = ofd.FileName;
exampleFileNameFolder = ofd.FileNameFull.Replace(ofd.FileName, "");