I want to output my key value pairs from a python dictionary as such:
key1 \t value1
key2 \t value2
I thought I could maybe do it like this:
for i in d:
print d.keys(i), d.values(i)
but obviously that's not how it goes as the keys()
and values()
don't take an argument.
This question is related to
python
dictionary
The dictionary:
d={'key1':'value1','key2':'value2','key3':'value3'}
Another one line solution:
print(*d.items(), sep='\n')
Output:
('key1', 'value1')
('key2', 'value2')
('key3', 'value3')
(but, since no one has suggested something like this before, I suspect it is not good practice)
A simple dictionary:
x = {'X':"yes", 'Y':"no", 'Z':"ok"}
To print a specific (key, value) pair in Python 3 (pair at index 1 in this example):
for e in range(len(x)):
print(([x for x in x.keys()][e], [x for x in x.values()][e]))
Output:
('X', 'yes')
('Y', 'no')
('Z', 'ok')
Here is a one liner solution to print all pairs in a tuple:
print(tuple(([x for x in x.keys()][i], [x for x in x.values()][i]) for i in range(len(x))))
Output:
(('X', 'yes'), ('Y', 'no'), ('Z', 'ok'))
Or, for Python 3:
for k,v in dict.items():
print(k, v)
To Print key-value pair, for example:
players = {
'lebron': 'lakers',
'giannis': 'milwakee bucks',
'durant': 'brooklyn nets',
'kawhi': 'clippers',
}
for player,club in players.items():
print(f"\n{player.title()} is the leader of {club}")
The above code, key-value pair:
'lebron': 'lakers', - Lebron is key and lakers is value
for loop - specify key, value in dictionary.item():
Now Print (Player Name is the leader of club).
the Output is:
#Lebron is the leader of lakers
#Giannis is the leader of milwakee bucks
#Durant is the leader of brooklyn nets
#Kawhi is the leader of clippers
for key, value in d.iteritems():
print key, '\t', value
If you want to sort the output by dict key you can use the collection package.
import collections
for k, v in collections.OrderedDict(sorted(d.items())).items():
print(k, v)
It works on python 3
A little intro to dictionary
d={'a':'apple','b':'ball'}
d.keys() # displays all keys in list
['a','b']
d.values() # displays your values in list
['apple','ball']
d.items() # displays your pair tuple of key and value
[('a','apple'),('b','ball')
Print keys,values method one
for x in d.keys():
print x +" => " + d[x]
Another method
for key,value in d.items():
print key + " => " + value
You can get keys using iter
>>> list(iter(d))
['a', 'b']
You can get value of key of dictionary using get(key, [value])
:
d.get('a')
'apple'
If key is not present in dictionary,when default value given, will return value.
d.get('c', 'Cat')
'Cat'
In addition to ways already mentioned.. can use 'viewitems', 'viewkeys', 'viewvalues'
>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]
Or
>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]
or using itemgetter
>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items()) #### for keys
['323', '332']
>>> map(itemgetter(1), dd.items()) #### for values
['3323', 232]
>>> d={'a':1,'b':2,'c':3}
>>> for kv in d.items():
... print kv[0],'\t',kv[1]
...
a 1
c 3
b 2
You can access your keys and/or values by calling items() on your dictionary.
for key, value in d.iteritems():
print(key, value)
Source: Stackoverflow.com