Delaying function in swift

Question

I don t have a code to sample or anything  because I have no idea how to do it  but can someone please tell me how to delay a function with swift for a set amount of time

User · Answer

Swift 3 and Above Version s  for a delay of 10 seconds      DispatchQueue main asyncAfter deadline   now     10     unowned self  in         self functionToCall

User · Answer

You can use GCD  in the example with a 10 second delay   Swift 2 let triggerTime    Int64 NSEC PER SEC    10  dispatch after dispatch time DISPATCH TIME NOW  triggerTime   dispatch get main queue         - gt  Void in     self functionToCall       Swift 3 and Swift 4 DispatchQueue main asyncAfter deadline   now     10 0  execute        self functionToCall       Swift 5 or Later  DispatchQueue main asyncAfter deadline   now     10 0              call any function

User · Answer

For adding argument to delay function   First setup a dictionary then add it as the userInfo  Unwrap the info with the timer as the argument   let arg   Int   42 let infoDict    String   AnyObject      argumentInt   arg   NSTimer scheduledTimerWithTimeInterval NSTimeInterval 3   target  self  selector   functionHereWithArgument    userInfo  infoDict  repeats  false    Then in the called function  func functionHereWithArgument  timer   NSTimer        if let userInfo   timer userInfo as  Dictionary lt String  AnyObject gt                 let argumentInt   Int    userInfo argumentInt  as  Int

User · Answer

NSTimer scheduledTimerWithTimeInterval NSTimeInterval 3   target  self  selector   functionHere   userInfo  nil  repeats  false    This would call the function functionHere   with a 3 seconds delay

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