count non-blank lines-of-code in bash

Question

In Bash  how do I count the number of non-blank lines of code in a project

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This command count number of non-blank lines  cat fileName   grep -v      wc -l grep -v    regular expression function is ignore blank lines

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cat file txt   awk  NF    wc -l

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Here s a Bash script that counts the lines of code in a project  It traverses a source tree recursively  and it excludes blank lines and single line comments that use           excluded is a regex for paths to exclude from line counting excluded  spec  node modules  README  lib  docs  csv  XLS  json  png   countLines         total is the total lines of code counted   total 0     -mindepth exclues the current directory         for file in  find   -mindepth 1 -name        grep -v   excluded    do       First sed  only count lines of code that are not commented with          Second sed  don t count blank lines        numLines is the lines of code     numLines  cat  file   sed        d    sed     s   d    wc -l         To exclude only blank lines and count comment lines  uncomment this       numLines  cat  file   sed     s   d    wc -l       total     total    numLines       echo       numLines  file   done   echo       total in total    echo Source code files  countLines echo Unit tests  cd spec countLines   Here s what the output looks like for my project   Source code files     2   buildDocs sh    24   countLines sh    15   css dashboard css    53   data un population provenance preprocess js    19   index html    5   server server js    2   server startServer sh    24   SpecRunner html    34   src computeLayout js    60   src configDiff js    18   src dashboardMirror js    37   src dashboardScaffold js    14   src data js    68   src dummyVis js    27   src layout js    28   src links js    5   src main js    52   src processActions js    86   src timeline js    73   src udc js    18   src wire js    664 in total Unit tests     230   ComputeLayoutSpec js    134   ConfigDiffSpec js    134   ProcessActionsSpec js    84   UDCSpec js    149   WireSpec js    731 in total   Enjoy  --Curran

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cat foo c   sed     s   d    wc -l   And if you consider comments blank lines   cat foo pl   sed     s   d    s   d    wc -l   Although  that s language dependent

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There s already a program for this on linux called  wc    Just  wc -l   c    and it gives you the total lines and the lines for each file

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If you want the sum of all non-blank lines for all files of a given file extension throughout a project   while read line do grep -cve    s      line  done  lt    lt  find  1 -name     2  -print    awk   s   1  END  print s     First arg is the project s base directory  second is the file extension  Sample usage     scriptname   Dropbox project src java   It s little more than a collection of previous solutions

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Script to recursively count all non-blank lines with a certain file extension in the current directory      usr bin env bash   echo 0  for ext in       do     for i in   find   -name    ext    do         sed     s   d   i   wc -l    skip blank lines          cat  i   wc -l     count all lines         echo        done done echo p q      dc    Sample usage     countlines sh  py  java  html

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The neatest command is grep -vc    fileName  with -c option  you don t even need wc -l

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grep -v    W     find -type f    grep -c      gt   path to lineCountFile txt   gives an aggregate count for all files in the current directory and its subdirectories   HTH

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bin bash find   -path    pma  -prune -o -path    blog  -prune -o -path    punbb  -prune -o -path    js 3rdparty  -prune -o -print   egrep    php   as   sql   css   js    grep -v    svn    xargs cat   sed     s   d    wc -l   The above will give you the total count of lines of code  blank lines removed  for a project  current folder and all subfolders recursively    In the above    blog     punbb     js 3rdparty  and    pma  are folders I blacklist as I didn t write the code in them  Also  php   as   sql   css   js are the extensions of the files being looked at  Any files with a different extension are ignored

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awk       space          x  END  print x     testfile

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There are many ways to do this  using common shell utilities   My solution is   grep -cve    s     lt file gt    This searches for lines in  lt file gt  the do not match  -v  lines that match the pattern  -e     s     which is the beginning of a line  followed by 0 or more whitespace characters  followed by the end of a line  ie  no content other then whitespace   and display a count of matching lines  -c  instead of the matching lines themselves   An advantage of this method over methods that involve piping into wc  is that you can specify multiple files and get a separate count for each file     grep -cve    s      hh  config hh 36 exceptions hh 48 layer hh 52 main hh 39

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It s kinda going to depend on the number of files you have in the project  In theory you could use  grep -c      lt list of files gt    Where you can fill the list of files by using the find utility   grep -c      find -type f    Would give you a line count per file

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cat  filename    grep          wc -l   should do the trick just fine

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rgrep      wc -l   gives the count of non blank lines in the current working directory

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If you want to use something other than a shell script  try CLOC      cloc counts blank lines  comment   lines  and physical lines of source   code in many programming languages  It   is written entirely in Perl with no   dependencies outside the standard   distribution of Perl v5 6 and higher    code from some external modules is   embedded within cloc  and so is quite   portable

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wc  counts lines  words  chars  so to count all lines  including blank ones  use   wc   py   To filter out the blank lines  you can use grep   grep -v    s      py   wc    -v  tells grep to output all lines except those that match     is the start of a line   s   is zero or more whitespace characters     is the end of a line   py is my example for all the files you wish to count  all python files in current dir  pipe output to wc  Off you go   I m answering my own  genuine  question  Couldn t find an stackoverflow entry that covered this

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grep -cvE     s          s     foo  -c   count -v   exclude -E   extended regex   comment lines  OR  empty lines   where        beginning of the line  s     whitespace        any number of previous characters or none        either   or          OR        end of the line   I post this becaus other options gave wrong answers for me  This worked with my java source  where comment lines start with   or    i use   on every line in multi-line comment

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This gives the count of number of lines without counting the blank lines   grep -v    filename wc -l   sed -e  s    g

[bash] count (non-blank) lines-of-code in bash

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