Iterate a list with indexes in Python

Question

I could swear I ve seen the function  or method  that takes a list  like this  3  7  19  and makes it into iterable list of tuples  like so    0 3    1 7    2 19   to use it instead of   for i in range len name of list        name of list i    something   but I can t remember the name and googling  iterate list  gets nothing

User · Answer

python enumerate function will be satisfied  your requirements  result   list enumerate  1 3 7 12    print result   output    0  1    1  3    2  7   3 12

User · Answer

If you have multiple lists  you can do this combining enumerate and zip   list1    1  2  3  4  5  list2    10  20  30  40  50  list3    100  200  300  400  500  for i   l1  l2  l3  in enumerate zip list1  list2  list3        print i  l1  l2  l3    Output   0 1 10 100 1 2 20 200 2 3 30 300 3 4 40 400 4 5 50 500   Note that parenthesis is required after i  Otherwise you get the error  ValueError  need more than 2 values to unpack

User · Answer

gt  gt  gt  a    3 4 5 6   gt  gt  gt  for i  val in enumerate a           print i  val     0 3 1 4 2 5 3 6  gt  gt  gt

User · Answer

Here it is a solution using map function    gt  gt  gt  a    3  7  19   gt  gt  gt  map lambda x   x  a x    range len a      0  3    1  7    2  19     And a solution using list comprehensions    gt  gt  gt  a    3 7 19   gt  gt  gt    x  a x   for x in range len a      0  3    1  7    2  19

User · Answer

Here s another using the zip function    gt  gt  gt  a    3  7  19   gt  gt  gt  zip range len a    a    0  3    1  7    2  19

User · Answer

Yep  that would be the enumerate function  Or more to the point  you need to do   list enumerate  3 7 19       0  3    1  7    2  19

[python] Iterate a list with indexes in Python

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