[bash] How to use 'find' to search for files created on a specific date?

How do I use the UNIX command find to search for files created on a specific date?

This question is related to bash unix find

The answer is


As pointed out by Max, you can't, but checking files modified or accessed is not all that hard. I wrote a tutorial about this, as late as today. The essence of which is to use -newerXY and ! -newerXY:

Example: To find all files modified on the 7th of June, 2007:

$ find . -type f -newermt 2007-06-07 ! -newermt 2007-06-08

To find all files accessed on the 29th of september, 2008:

$ find . -type f -newerat 2008-09-29 ! -newerat 2008-09-30

Or, files which had their permission changed on the same day:

$ find . -type f -newerct 2008-09-29 ! -newerct 2008-09-30

If you don't change permissions on the file, 'c' would normally correspond to the creation date, though.


You could do this:

find ./ -type f -ls |grep '10 Sep'

Example:

[root@pbx etc]# find /var/ -type f -ls | grep "Dec 24"
791235    4 -rw-r--r--   1 root     root           29 Dec 24 03:24 /var/lib/prelink/full
798227  288 -rw-r--r--   1 root     root       292323 Dec 24 23:53 /var/log/sa/sar24
797244  320 -rw-r--r--   1 root     root       321300 Dec 24 23:50 /var/log/sa/sa24

@Max: is right about the creation time.

However, if you want to calculate the elapsed days argument for one of the -atime, -ctime, -mtime parameters, you can use the following expression

ELAPSED_DAYS=$(( ( $(date +%s) - $(date -d '2008-09-24' +%s) ) / 60 / 60 / 24 - 1 ))

Replace "2008-09-24" with whatever date you want and ELAPSED_DAYS will be set to the number of days between then and today. (Update: subtract one from the result to align with find's date rounding.)

So, to find any file modified on September 24th, 2008, the command would be:

find . -type f -mtime $(( ( $(date +%s) - $(date -d '2008-09-24' +%s) ) / 60 / 60 / 24 - 1 ))

This will work if your version of find doesn't support the -newerXY predicates mentioned in @Arve:'s answer.


I found this scriplet in a script that deletes all files older than 14 days:

CNT=0
for i in $(find -type f -ctime +14); do
  ((CNT = CNT + 1))
  echo -n "." >> $PROGRESS
  rm -f $i
done
echo deleted $CNT files, done at $(date "+%H:%M:%S") >> $LOG

I think a little additional "man find" and looking for the -ctime / -atime etc. parameters will help you here.


It's two steps but I like to do it this way:

First create a file with a particular date/time. In this case, the file is 2008-10-01 at midnight

touch -t 0810010000 /tmp/t

Now we can find all files that are newer or older than the above file (going by file modified date. You can also use -anewer for accessed and -cnewer file status changed).

find / -newer /tmp/t
find / -not -newer /tmp/t

You could also look at files between certain dates by creating two files with touch

touch -t 0810010000 /tmp/t1
touch -t 0810011000 /tmp/t2

This will find files between the two dates & times

find / -newer /tmp/t1 -and -not -newer /tmp/t2

You can't. The -c switch tells you when the permissions were last changed, -a tests the most recent access time, and -m tests the modification time. The filesystem used by most flavors of Linux (ext3) doesn't support a "creation time" record. Sorry!


find location -ctime time_period

Examples of time_period:

  • More than 30 days ago: -ctime +30

  • Less than 30 days ago: -ctime -30

  • Exactly 30 days ago: -ctime 30


cp `ls -ltr | grep 'Jun 14' | perl -wne 's/^.*\s+(\S+)$/$1/; print $1 . "\n";'` /some_destination_dir

With the -atime, -ctime, and -mtime switches to find, you can get close to what you want to achieve.


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