[python] Plotting multiple lines, in different colors, with pandas dataframe

I have a dataframe that looks like the following

   color  x   y
0    red  0   0
1    red  1   1
2    red  2   2
3    red  3   3
4    red  4   4
5    red  5   5
6    red  6   6
7    red  7   7
8    red  8   8
9    red  9   9
10  blue  0   0
11  blue  1   1
12  blue  2   4
13  blue  3   9
14  blue  4  16
15  blue  5  25
16  blue  6  36
17  blue  7  49
18  blue  8  64
19  blue  9  81

I ultimately want two lines, one blue, one red. The red line should essentially be y=x and the blue line should be y=x^2

When I do the following:

df.plot(x='x', y='y')

The output is this:

Is there a way to make pandas know that there are two sets? And group them accordingly. I'd like to be able to specify the column color as the set differentiator

You could use groupby to split the DataFrame into subgroups according to the color:

for key, grp in df.groupby(['color']):

import numpy as np
import pandas as pd
import matplotlib.pyplot as plt

df = pd.read_table('data', sep='\s+')
fig, ax = plt.subplots()

for key, grp in df.groupby(['color']):
    ax = grp.plot(ax=ax, kind='line', x='x', y='y', c=key, label=key)

plt.legend(loc='best')
plt.show()

yields

If you have seaborn installed, an easier method that does not require you to perform pivot:

import seaborn as sns

sns.lineplot(data=df, x='x', y='y', hue='color')

You can use this code to get your desire output

import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame({'color': ['red','red','red','blue','blue','blue'], 'x': [0,1,2,3,4,5],'y': [0,1,2,9,16,25]})
print df

  color  x   y
0   red  0   0
1   red  1   1
2   red  2   2
3  blue  3   9
4  blue  4  16
5  blue  5  25

To plot graph

a = df.iloc[[i for i in xrange(0,len(df)) if df['x'][i]==df['y'][i]]].plot(x='x',y='y',color = 'red')
df.iloc[[i for i in xrange(0,len(df)) if df['y'][i]== df['x'][i]**2]].plot(x='x',y='y',color = 'blue',ax=a)

plt.show()

Output