How can I generate a list of consecutive numbers

Question

Say if you had a number input 8 in python and you wanted to generate a list of consecutive numbers up to 8 like   0  1  2  3  4  5  6  7  8    How could you do this

User · Answer

import numpy as np  myList   np linspace 0  100  1000   Generates 1000 numbers from 0 to 100 in equal intervals

User · Answer

Just to give you another example  although range value  is by far the best way to do this  this might help you later on something else   list      calc   0  while int calc   lt  9      list append calc      calc   int calc    1  print list  0  1  2  3  4  5  6  7  8

User · Answer

Depending on how you want the result  you can also print each number in a for loop   def numbers        for i in range int input  How far do you wanna go      1           print i    So if the user input was 7 for example   How far do you wanna go  7 0 1 2 3 4 5 6 7   You can also delete the   1  in the for loop and place it on the print statement  which will change it to starting at 1 instead of 0

User · Answer

Using Python s built in range function   Python 2  input   8 output   range input   1   print output  0  1  2  3  4  5  6  7  8    Python 3  input   8 output   list range input   1    print output   0  1  2  3  4  5  6  7  8

User · Answer

In Python 3  you can use the builtin range function like this   gt  gt  gt  list range 9    0  1  2  3  4  5  6  7  8    Note 1  Python 3 x s range function  returns a range object  If you want a list you need to explicitly convert that to a list  with the list function like I have shown in the answer   Note 2  We pass number 9 to range function because  range function will generate numbers till the given number but not including the number  So  we give the actual number   1   Note 3  There is a small difference in functionality of range in Python 2 and 3  You can read more about that in this answer

User · Answer

You can use list comprehensions for this problem as it will solve it in only two lines  Code- n   int input  quot Enter the range of the list  n quot    l1    i for i in range n    Creates list of numbers in the range 0 to n if   name       quot   main   quot       print l1   Thank you

User · Answer

Note  - Certainly in python-3x you need to use Range function It works to generate numbers on demand  standard method to use Range function to make a list of consecutive numbers is   x list range 10     list  will make all numbers generated by range in a list  number in range  10  is an option you can change as you want print  x   Output is   0 1 2 3 4 5 6 7 8 9    Also if you want to make an function to generate a list of consecutive numbers by using Range function watch this code     def  consecutive numbers n        list  i for i in range n       return  list  print consecutive numbers 10     Good Luck

User · Answer

You can use itertools count   to generate unbounded sequences    itertools is in the Python standard library    Docs here  https   docs python org 3 library itertools html itertools count

[python] How can I generate a list of consecutive numbers?

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