Regex to get string between curly braces

Question

Unfortunately  despite having tried to learn regex at least one time a year for as many years as I can remember  I always forget as I use them so infrequently  This year my new year s resolution is to not try and learn regex again - So this year to save me from tears I ll give it to Stack Overflow   Last Christmas remix    I want to pass in a string in this format  getThis   and be returned the string getThis  Could anyone be of assistance in helping to stick to my new year s resolution     Related questions on Stack Overflow    How can one turn regular quotes  i e    39    quot   into LaTeX TeX quotes  i e     39       39   39   Regex  To pull out a sub-string between two tags in a string Regex to replace all  n in a String  but no those inside  code    code  tag

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You want to use regex lookahead and lookbehind  This will give you only what is inside the curly braces        lt

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- delimiter          - opening literal brace escaped because it is a special character used for quantifiers eg  2 3           - start capturing          - character class consisting of          - not          - a closing brace  no escaping necessary because special characters in a character class are different           - one or more of the character class          - end capturing          - the closing literal brace          - delimiter

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Even this helps me while trying to solve someone s problem      Split the contents inside curly braces      having a pattern like      day   1   count   100     For example    include  lt iostream gt    include  lt regex gt    include lt string gt   using namespace std    int main             string to be searched     string s      day   1   count   100     day   2   count   100            regex expression for pattern to be searched      regex e       a-z    0-9             regex token iterator lt string  iterator gt  rend       regex token iterator lt string  iterator gt  a   s begin    s end    e        while  a  rend  cout  lt  lt        lt  lt   a    lt  lt           cout  lt  lt  endl       return 0       Output      day   1   count   100      day   2   count   100

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If your string will always be of that format  a regex is overkill    gt  gt  gt  var g   getThis     gt  gt  gt  g substring 1 g length-1   getThis    substring 1 means to start one character in  just past the first    and  g length-1  means to take characters until  but not including  the character at the string length minus one  This works because the position is zero-based  i e  g length-1 is the last position   For readers other than the original poster  If it has to be a regex  use             if you want to allow empty strings  or             if you want to only match when there is at least one character between the curly braces   Breakdown       start the regex pattern      a literal curly brace      start capturing      start defining a class of characters to capture        anything other than        OK  that s our whole class definition    any number of characters matching that class we just defined     done capturing     a literal curly brace must immediately follow what we captured     end the regex pattern

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Try              That means  match any character between   and    but don t be greedy - match the shortest string which ends with    the   stops   being greedy   The parentheses let you extract the matched portion   Another way would be                This matches any character except a   char  another way of not being greedy

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Even this helps me while trying to solve someone s problem      Split the contents inside curly braces      having a pattern like      day   1   count   100     For example    include  lt iostream gt    include  lt regex gt    include lt string gt   using namespace std    int main             string to be searched     string s      day   1   count   100     day   2   count   100            regex expression for pattern to be searched      regex e       a-z    0-9             regex token iterator lt string  iterator gt  rend       regex token iterator lt string  iterator gt  a   s begin    s end    e        while  a  rend  cout  lt  lt        lt  lt   a    lt  lt           cout  lt  lt  endl       return 0       Output      day   1   count   100      day   2   count   100

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Try this  let path      id   name   age    const paramsPattern                 g  let extractParams   path match paramsPattern   console log  extractParams   extractParams     prints all the names between        id    name    age

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Try this                 g   For example   Welcome to RegExr v2 1 by   gskinner com      ssd sd  hosted by Media Temple    will return gskinner com  ssd sd

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If your string will always be of that format  a regex is overkill    gt  gt  gt  var g   getThis     gt  gt  gt  g substring 1 g length-1   getThis    substring 1 means to start one character in  just past the first    and  g length-1  means to take characters until  but not including  the character at the string length minus one  This works because the position is zero-based  i e  g length-1 is the last position   For readers other than the original poster  If it has to be a regex  use             if you want to allow empty strings  or             if you want to only match when there is at least one character between the curly braces   Breakdown       start the regex pattern      a literal curly brace      start capturing      start defining a class of characters to capture        anything other than        OK  that s our whole class definition    any number of characters matching that class we just defined     done capturing     a literal curly brace must immediately follow what we captured     end the regex pattern

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- delimiter          - opening literal brace escaped because it is a special character used for quantifiers eg  2 3           - start capturing          - character class consisting of          - not          - a closing brace  no escaping necessary because special characters in a character class are different           - one or more of the character class          - end capturing          - the closing literal brace          - delimiter

User · Answer

If your string will always be of that format  a regex is overkill    gt  gt  gt  var g   getThis     gt  gt  gt  g substring 1 g length-1   getThis    substring 1 means to start one character in  just past the first    and  g length-1  means to take characters until  but not including  the character at the string length minus one  This works because the position is zero-based  i e  g length-1 is the last position   For readers other than the original poster  If it has to be a regex  use             if you want to allow empty strings  or             if you want to only match when there is at least one character between the curly braces   Breakdown       start the regex pattern      a literal curly brace      start capturing      start defining a class of characters to capture        anything other than        OK  that s our whole class definition    any number of characters matching that class we just defined     done capturing     a literal curly brace must immediately follow what we captured     end the regex pattern

User · Answer

Try              That means  match any character between   and    but don t be greedy - match the shortest string which ends with    the   stops   being greedy   The parentheses let you extract the matched portion   Another way would be                This matches any character except a   char  another way of not being greedy

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Try this one  according to http   www regextester com it works for js normaly

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var re             var m     helloworld   match re   if  m    null      console log m 0  replace re    1       The simpler  replace                 1   unfortunately returns the entire string if the regex does not match  The above code snippet can more easily detect a match

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This one works in Textmate and it matches everything in a CSS file between the curly brackets       s              selector      matches here including white space         If you want to further be able to return the content  then wrap it all in one more set of parentheses like so        s              and you can access the contents via  1   This also works for functions  but I haven t tested it with nested curly brackets

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Here s a simple solution using javascript replace  var st     getThis     st   st replace        gi          getThis    As the accepted answer above points out the original problem is easily solved with substring  but using replace can solve the more complicated use cases  If you have a string like  randomstring999 fieldname   You use a slightly different pattern to get fieldname  var nameAttr    randomstring999 fieldname     var justName   nameAttr replace          gi          fieldname

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Try this one  according to http   www regextester com it works for js normaly

User · Answer

This one works in Textmate and it matches everything in a CSS file between the curly brackets       s              selector      matches here including white space         If you want to further be able to return the content  then wrap it all in one more set of parentheses like so        s              and you can access the contents via  1   This also works for functions  but I haven t tested it with nested curly brackets

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Try this                 g   For example   Welcome to RegExr v2 1 by   gskinner com      ssd sd  hosted by Media Temple    will return gskinner com  ssd sd

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You can use this regex recursion to match everythin between  even another     like a JSON text

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This one matches everything even if it finds multiple closing curly braces in the middle       s S      Example       quot foo quot          quot bar quot   1       quot baz quot   1

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Here s a simple solution using javascript replace  var st     getThis     st   st replace        gi          getThis    As the accepted answer above points out the original problem is easily solved with substring  but using replace can solve the more complicated use cases  If you have a string like  randomstring999 fieldname   You use a slightly different pattern to get fieldname  var nameAttr    randomstring999 fieldname     var justName   nameAttr replace          gi          fieldname

User · Answer

- delimiter          - opening literal brace escaped because it is a special character used for quantifiers eg  2 3           - start capturing          - character class consisting of          - not          - a closing brace  no escaping necessary because special characters in a character class are different           - one or more of the character class          - end capturing          - the closing literal brace          - delimiter

User · Answer

Try              That means  match any character between   and    but don t be greedy - match the shortest string which ends with    the   stops   being greedy   The parentheses let you extract the matched portion   Another way would be                This matches any character except a   char  another way of not being greedy

User · Answer

var re             var m     helloworld   match re   if  m    null      console log m 0  replace re    1       The simpler  replace                 1   unfortunately returns the entire string if the regex does not match  The above code snippet can more easily detect a match

User · Answer

Try              That means  match any character between   and    but don t be greedy - match the shortest string which ends with    the   stops   being greedy   The parentheses let you extract the matched portion   Another way would be                This matches any character except a   char  another way of not being greedy

User · Answer

i have looked into the other answers  and a vital logic seems to be missing from them   ie  select everything between two CONSECUTIVE brackets but NOT the brackets  so  here is my answer

User · Answer

You want to use regex lookahead and lookbehind  This will give you only what is inside the curly braces        lt

User · Answer

You can use this regex recursion to match everythin between  even another     like a JSON text

User · Answer

Regex for getting arrays of string with curly braces enclosed occurs in string  rather than just finding first occurrence                 gm

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Regex for getting arrays of string with curly braces enclosed occurs in string  rather than just finding first occurrence                 gm

User · Answer

- delimiter          - opening literal brace escaped because it is a special character used for quantifiers eg  2 3           - start capturing          - character class consisting of          - not          - a closing brace  no escaping necessary because special characters in a character class are different           - one or more of the character class          - end capturing          - the closing literal brace          - delimiter

User · Answer

Try this  let path      id   name   age    const paramsPattern                 g  let extractParams   path match paramsPattern   console log  extractParams   extractParams     prints all the names between        id    name    age

User · Answer

i have looked into the other answers  and a vital logic seems to be missing from them   ie  select everything between two CONSECUTIVE brackets but NOT the brackets  so  here is my answer

User · Answer

This one matches everything even if it finds multiple closing curly braces in the middle       s S      Example       quot foo quot          quot bar quot   1       quot baz quot   1

User · Answer

If your string will always be of that format  a regex is overkill    gt  gt  gt  var g   getThis     gt  gt  gt  g substring 1 g length-1   getThis    substring 1 means to start one character in  just past the first    and  g length-1  means to take characters until  but not including  the character at the string length minus one  This works because the position is zero-based  i e  g length-1 is the last position   For readers other than the original poster  If it has to be a regex  use             if you want to allow empty strings  or             if you want to only match when there is at least one character between the curly braces   Breakdown       start the regex pattern      a literal curly brace      start capturing      start defining a class of characters to capture        anything other than        OK  that s our whole class definition    any number of characters matching that class we just defined     done capturing     a literal curly brace must immediately follow what we captured     end the regex pattern

[javascript] Regex to get string between curly braces

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