[javascript] Hide/Show components in react native

I'm really new to React Native and I'm wondering how can I hide/show a component.
Here's my test case:

<TextInput
    onFocus={this.showCancel()}
    onChangeText={(text) => this.doSearch({input: text})} />

<TouchableHighlight 
    onPress={this.hideCancel()}>
    <View>
        <Text style={styles.cancelButtonText}>Cancel</Text>
    </View>
</TouchableHighlight>

I have a TextInput component, what I want is to show the TouchableHighlight when the input gets the focus, then hide the TouchableHighlight when the user press the cancel button.

I don´t know how to "access" the TouchableHighlight component in order to hide/show it inside of my functions showCancel/hideCancel.
Also, how can I hide the button from the very beginning?

checkincheckout = () => {
        this.setState({ visible: !this.state.visible })
}

render() {
        return (
{this.state.visible == false ?
        <View style={{ alignItems: 'center', flexDirection: 'row', marginTop: 50 }}>

        <View style={{ flex: 1, alignItems: 'center', flexDirection: 'column' }}>

            <TouchableOpacity onPress={() => this.checkincheckout()}>

                <Text style={{ color: 'white' }}>Click to Check in</Text>

            </TouchableOpacity>

        </View>

    </View>
:
<View style={{ alignItems: 'center', flexDirection: 'row', marginTop: 50 }}>

<View style={{ flex: 1, alignItems: 'center', flexDirection: 'column' }}>

   <TouchableOpacity onPress={() => this.checkincheckout()}>

        <Text style={{ color: 'white' }}>Click to Check out</Text>

    </TouchableOpacity>

</View>

</View>
 }

);
}

thats all. enjoy your coding...

If you want to hide it but keep the space occupied by the component like css's visibility: hidden setting in the component's style opacity: 0 should do the trick.

Depending on the component other steps in disabling the functionality might be required as interaction with an invisible item is possible.

Actually, in iOS development by react-native when I use display: 'none' or something like below:

const styles = StyleSheet.create({
  disappearImage: {
    width: 0,
    height: 0
  }
});

The iOS doesn't load anything else of the Image component like onLoad or etc, so I decided to use something like below:

const styles = StyleSheet.create({
  disappearImage: {
    width: 1,
    height: 1,
    position: 'absolute',
    top: -9000,
    opacity: 0
  }
});

I solve this problem like this:

<View style={{ display: stateLoad ? 'none' : undefined }} />

I needed to switch between two images. With conditional switching between them there was 5sec delay with no image displayed.

I'm using approach from downvoted amos answer. Posting as new answer because it's hard to put code into comment with proper formatting.

Render function:

<View style={styles.logoWrapper}>
  <Image
    style={[styles.logo, loading ? styles.hidden : {}]}
    source={require('./logo.png')} />
  <Image
    style={[styles.logo, loading ? {} : styles.hidden]}
    source={require('./logo_spin.gif')} />
</View>

Styles:

var styles = StyleSheet.create({
  logo: {
    width: 200,
    height: 200,
  },
  hidden: {
    width: 0,
    height: 0,
  },
});

i am just using below method to hide or view a button. hope it will help you. just updating status and adding hide css is enough for me

constructor(props) {
   super(props);
      this.state = {
      visibleStatus: false
   };
}
updateStatusOfVisibility () {
   this.setStatus({
      visibleStatus: true
   });
}
hideCancel() {
   this.setStatus({visibleStatus: false});
}

render(){
   return(
    <View>
        <TextInput
            onFocus={this.showCancel()}
            onChangeText={(text) => {this.doSearch({input: text}); this.updateStatusOfVisibility()}} />

         <TouchableHighlight style={this.state.visibleStatus ? null : { display: "none" }}
             onPress={this.hideCancel()}>
            <View>
                <Text style={styles.cancelButtonText}>Cancel</Text>
            </View>
        </TouchableHighlight>
     </View>)
}

In react or react native the way component hide/show or add/remove does not work like in android or iOS. Most of us think there would be the similar strategy like

View.hide = true or parentView.addSubView(childView)

But the way react native work is completely different. The only way to achieve this kind of functionality is to include your component in your DOM or remove from DOM.

Here in this example I am going set the visibility of text view based on the button click.

The idea behind this task is the create a state variable called state having the initial value set to false when the button click event happens then it value toggles. Now we will use this state variable during the creation of component.

import renderIf from './renderIf'

class FetchSample extends Component {
  constructor(){
    super();
    this.state ={
      status:false
    }
  }

  toggleStatus(){
    this.setState({
      status:!this.state.status
    });
    console.log('toggle button handler: '+ this.state.status);
  }

  render() {
    return (
      <View style={styles.container}>
        {renderIf(this.state.status)(
          <Text style={styles.welcome}>
            I am dynamic text View
          </Text>
        )}

        <TouchableHighlight onPress={()=>this.toggleStatus()}>
          <Text>
            touchme
          </Text>
        </TouchableHighlight>
      </View>
    );
  }
}

the only one thing to notice in this snippet is renderIf which is actually a function which will return the component passed to it based on the boolean value passed to it.

renderIf(predicate)(element)

renderif.js

'use strict';
const isFunction = input => typeof input === 'function';
export default predicate => elemOrThunk =>
  predicate ? (isFunction(elemOrThunk) ? elemOrThunk() : elemOrThunk) : null;

in render() you can conditionally show the JSX or return null as in:

render(){
    return({yourCondition ? <yourComponent /> : null});
}

In your render function:

{ this.state.showTheThing && 
  <TextInput/>
}

Then just do:

this.setState({showTheThing: true})  // to show it  
this.setState({showTheThing: false}) // to hide it

Hide And Show parent view of Activity Indicator

constructor(props) {
  super(props)

  this.state = {
    isHidden: false
  }  
} 

Hide and Show as Follow

{
   this.state.isHidden ?  <View style={style.activityContainer} hide={false}><ActivityIndicator size="small" color="#00ff00" animating={true}/></View> : null
}

Full reference

render() {
    return (
       <View style={style.mainViewStyle}>
          <View style={style.signinStyle}>
           <TextField placeholder='First Name' keyboardType='default' onChangeFirstName={(text) => this.setState({firstName: text.text})}/>
           <TextField placeholder='Last Name' keyboardType='default' onChangeFirstName={(text) => this.setState({lastName: text.text})}/>
           <TextField placeholder='Email' keyboardType='email-address' onChangeFirstName={(text) => this.setState({email: text.text})}/>
           <TextField placeholder='Phone Number' keyboardType='phone-pad' onChangeFirstName={(text) => this.setState({phone: text.text})}/>
           <TextField placeholder='Password' secureTextEntry={true} keyboardType='default' onChangeFirstName={(text) => this.setState({password: text.text})}/>
           <Button  style={AppStyleSheet.buttonStyle} title='Sign up' onPress={() => this.onSignupPress()} color='red' backgroundColor='black'/>
          </View>
          {
            this.state.isHidden ?  <View style={style.activityContainer}><ActivityIndicator size="small" color="#00ff00" animating={true}/></View> : null
          }
      </View>
   );
}

On Button presss set state as follow

onSignupPress() {
  this.setState({isHidden: true})
}

When you need to hide

this.setState({isHidden: false})

I had the same issue where I would want to show / hide Views, but I really didn't want the UI jumping around when things were added/removed or necessarily to deal with re-rendering.

I wrote a simple Component to deal with it for me. Animated by default, but easy to toggle. I put it on GitHub and NPM with a readme, but all the code is below.

npm install --save react-native-hideable-view

import React, { Component, PropTypes } from 'react';
import { Animated  } from 'react-native';

class HideableView extends Component {
  constructor(props) {
    super(props);
    this.state = {
      opacity: new Animated.Value(this.props.visible ? 1 : 0)
    }
  }

  animate(show) {
    const duration = this.props.duration ? parseInt(this.props.duration) : 500;
    Animated.timing(
      this.state.opacity, {
        toValue: show ? 1 : 0,
        duration: !this.props.noAnimation ? duration : 0
      }
    ).start();
  }

  shouldComponentUpdate(nextProps) {
    return this.props.visible !== nextProps.visible;
  }

  componentWillUpdate(nextProps, nextState) {
    if (this.props.visible !== nextProps.visible) {
      this.animate(nextProps.visible);
    }
  }

  render() {
    if (this.props.removeWhenHidden) {
      return (this.visible && this.props.children);
    }
    return (
      <Animated.View style={{opacity: this.state.opacity}}>
        {this.props.children}
      </Animated.View>
    )
  }
}

HideableView.propTypes = {
  visible: PropTypes.bool.isRequired,
  duration: PropTypes.number,
  removeWhenHidden: PropTypes.bool,
  noAnimation: PropTypes.bool
}

export default HideableView;

just use

style={ width:0, height:0 } // to hide

You can use the conditions for show and hide the components

constructor(){

    super();

    this.state ={

      isVisible:true

    }
  }

  ToggleFunction = () => {

    this.setState(state => ({

      isVisible: !state.isVisible

    }));

  };

  render() {
  
    return (

      <View style={styles.MainContainer}>

      {

        this.state.isVisible ? <Text style= {{ fontSize: 20, color: "red", textAlign: 'center' }}> Hello World! </Text> : null
      }

      <Button title="Toggle Visibility" onPress={this.ToggleFunction} />

      </View>
    );
  }

// You can use a state to control wether the component is showing or not
const [show, setShow] = useState(false); // By default won't show

// In return(
{
    show && <ComponentName />
}

/* Use this to toggle the state, this could be in a function in the 
main javascript or could be triggered by an onPress */

show == true ? setShow(false) : setShow(true)

// Example:
const triggerComponent = () => {
    show == true ? setShow(false) : setShow(true)
}

// Or
<SomeComponent onPress={() => {show == true ? setShow(false) : setShow(true)}}/>

I would vouch for using the opacity-method if you do not want to remove the component from your page, e.g. hiding a WebView.

<WebView
   style={{opacity: 0}} // Hide component
   source={{uri: 'https://www.google.com/'}}
 />

This is useful if you need to submit a form to a 3rd party website.

The only way to show or hide a component in react native is checking a value of a parameter of app state like state or props. I provided a complete example as below:

import React, {Component} from 'react';
import {View,Text,TextInput,TouchableHighlight} from 'react-native'

class App extends Component {

    constructor(props){
        super(props);
        this.state={
            show:false
        }
}

    showCancel=()=>{
        this.setState({show:true})
    };

    hideCancel=()=>{
        this.setState({show:false})
    };

    renderTouchableHighlight(){
        if(this.state.show){
           return(
               <TouchableHighlight
                   style={{borderColor:'black',borderWidth:1,marginTop:20}}
                   onPress={this.hideCancel}>
                   <View>
                       <Text>Cancel</Text>
                   </View>
               </TouchableHighlight>
           )
        }
        return null;
    }

    render() {


        return (
            <View style={{justifyContent:'center',alignItems:'center',flex:1}}>
                <TextInput
                    style={{borderColor:'black',borderBottomWidth:1}}
                    onFocus={this.showCancel}
                />
                {this.renderTouchableHighlight()}

            </View>
        );
    }
}

export default App;

Just simply use this because I wanted to use the "useRef" conditions were not an option for me. You can use this suppose when you want to use useRef hook and press the button.

   <Button
      ref={uploadbtn}
      buttonStyle={{ width: 0, height: 0, opacity: 0, display: "none" }}
      onPress={pickImage}
    />

If you need the component to remain loaded but hidden you can set the opacity to 0. (I needed this for expo camera for instance)

//in constructor    
this.state = {opacity: 100}

/in component
style = {{opacity: this.state.opacity}}

//when you want to hide
this.setState({opacity: 0})

Most of the time i'm doing something like this :

class MyComponent extends React.Component {
  constructor(props) {
    super(props);
    this.state = {isHidden: false};
    this.onPress = this.onPress.bind(this);
  }
  onPress() {
    this.setState({isHidden: !this.state.isHidden})
  }
  render() {
    return (
      <View style={styles.myStyle}>

        {this.state.isHidden ? <ToHideAndShowComponent/> : null}

        <Button title={this.state.isHidden ? "SHOW" : "HIDE"} onPress={this.onPress} />
      </View>
    );
  }
}

If you're kind of new to programming, this line must be strange to you :

{this.state.isHidden ? <ToHideAndShowComponent/> : null}

This line is equivalent to

if (this.state.isHidden)
{
  return ( <ToHideAndShowComponent/> );
}
else
{
  return null;
}

But you can't write an if/else condition in JSX content (e.g. the return() part of a render function) so you'll have to use this notation.

This little trick can be very useful in many cases and I suggest you to use it in your developments because you can quickly check a condition.

Regards,

An additional option is to apply absolute positioning via styling, setting the hidden component in out-of-screen coordinates:

<TextInput
    onFocus={this.showCancel()}
    onChangeText={(text) => this.doSearch({input: text})}
    style={this.state.hide ? {position: 'absolute', top: -200} : {}}
/>

Unlike in some of the previous suggestions, this would hide your component from view BUT will also render it (keep it in the DOM), thus making it truly invisible.

Very Easy. Just change to () => this.showCancel() like below:

<TextInput
        onFocus={() => this.showCancel() }
        onChangeText={(text) => this.doSearch({input: text})} />

<TouchableHighlight 
    onPress={this.hideCancel()}>
    <View>
        <Text style={styles.cancelButtonText}>Cancel</Text>
    </View>
</TouchableHighlight>

The following example is coding in typescript with Hooks.

import React, { useState, useEffect } from "react";

........

const App = () => {

   const [showScrollView, setShowScrollView] = useState(false);

   ......

   const onPress = () => {
    // toggle true or false
    setShowScrollView(!showScrollView);
  }

  ......

      </MapboxGL.ShapeSource>
        <View>{showScrollView ? (<DetailsScrollView />) : null}</View>
      </MapboxGL.MapView>
  ......

}

constructor(props) {
    super(props);
    this.state = {
      visible: true,
}
}

declare visible false so by default modal / view are hide

example = () => {

 this.setState({ visible: !this.state.visible })

}

**Function call **

{this.state.visible == false ?
        <View>
            <TouchableOpacity
              onPress= {() => this.example()}>   // call function
                          <Text>
                            show view
                          </Text>
            </TouchableOpacity>

</View>
:
 <View>
    <TouchableOpacity
              onPress= {() => this.example()}>
                          <Text>
                            hide view
                          </Text>
            </TouchableOpacity>
</View> 
 }

React Native's layout has the display property support, similar to CSS. Possible values: none and flex (default). https://facebook.github.io/react-native/docs/layout-props#display

<View style={{display: 'none'}}> </View>

You can use my module react-native-display to show/hide components.