String is
ex="test1, test2, test3, test4, test5"
when I use
ex.split(",").first
it returns
"test1"
Now I want to get the remaining items, i.e. `"test2, test3, test4, test5". If I use
ex.split(",").last
it returns only
"test5"
How to get all the remaining items skipping first one?
You probably mistyped a few things. From what I gather, you start with a string such as:
string = "test1, test2, test3, test4, test5"
Then you want to split it to keep only the significant substrings:
array = string.split(/, /)
And in the end you only need all the elements excluding the first one:
# We extract and remove the first element from array
first_element = array.shift
# Now array contains the expected result, you can check it with
puts array.inspect
Did that answer your question ?
ex.split(',', 2).last
The 2 at the end says: split into 2 pieces, not more.
normally split will cut the value into as many pieces as it can, using a second value you can limit how many pieces you will get. Using ex.split(',', 2) will give you:
["test1", "test2, test3, test4, test5"]
as an array, instead of:
["test1", "test2", "test3", "test4", "test5"]
Sorry a bit late to the party and a bit surprised that nobody mentioned the drop method:
ex="test1, test2, test3, test4, test5"
ex.split(",").drop(1).join(",")
=> "test2,test3,test4,test5"
Since you've got an array, what you really want is Array#slice, not split.
rest = ex.slice(1 .. -1)
# or
rest = ex[1 .. -1]
Try split(",")[i] where i is the index in result array. split gives array below
["test1", " test2", " test3", " test4", " test5"]
whose element can be accessed by index.
You can also do this:
String is ex="test1, test2, test3, test4, test5"
array = ex.split(/,/)
array.size.times do |i|
p array[i]
end
ex="test1,test2,test3,test4,test5"
all_but_first=ex.split(/,/)[1..-1]
if u want to use them as an array u already knew, else u can use every one of them as a different parameter ... try this :
parameter1,parameter2,parameter3,parameter4,parameter5 = ex.split(",")
Source: Stackoverflow.com