[php] Get characters after last / in url

I want to get the characters after the last / in an url like http://www.vimeo.com/1234567

How do I do with php?

$str = "http://www.vimeo.com/1234567";
$s = explode("/",$str);
print end($s);

You can use substr and strrchr:

$url = 'http://www.vimeo.com/1234567';
$str = substr(strrchr($url, '/'), 1);
echo $str;      // Output: 1234567

$str = basename($url);

Here's a beautiful dynamic function I wrote to remove last part of url or path.

/**
 * remove the last directories
 *
 * @param $path the path
 * @param $level number of directories to remove
 *
 * @return string
 */
private function removeLastDir($path, $level)
{
    if(is_int($level) && $level > 0){
        $path = preg_replace('#\/[^/]*$#', '', $path);
        return $this->removeLastDir($path, (int) $level - 1);
    }
    return $path;
}

array_pop(explode("/", "http://vimeo.com/1234567")); will return the last element of the example url

You could explode based on "/", and return the last entry:

print end( explode( "/", "http://www.vimeo.com/1234567" ) );

That's based on blowing the string apart, something that isn't necessary if you know the pattern of the string itself will not soon be changing. You could, alternatively, use a regular expression to locate that value at the end of the string:

$url = "http://www.vimeo.com/1234567";

if ( preg_match( "/\d+$/", $url, $matches ) ) {
    print $matches[0];
}

Two one liners - I suspect the first one is faster but second one is prettier and unlike end() and array_pop(), you can pass the result of a function directly to current() without generating any notice or warning since it doesn't move the pointer or alter the array.

$var = 'http://www.vimeo.com/1234567';

// VERSION 1 - one liner simmilar to DisgruntledGoat's answer above
echo substr($a,(strrpos($var,'/') !== false ? strrpos($var,'/') + 1 : 0));

// VERSION 2 - explode, reverse the array, get the first index.
echo current(array_reverse(explode('/',$var)));