[bash] Renaming part of a filename

I have loads of files which look like this:

DET01-ABC-5_50-001.dat
...
DET01-ABC-5_50-0025.dat

and I want them to look like this:

DET01-XYZ-5_50-001.dat
...
DET01-XYZ-5_50-0025.dat

How can I do this?

This question is related to bash filenames rename

The answer is


You'll need to learn how to use sed http://unixhelp.ed.ac.uk/CGI/man-cgi?sed

And also to use for so you can loop through your file entries http://www.cyberciti.biz/faq/bash-for-loop/

Your command will look something like this, I don't have a term beside me so I can't check

for i in `dir` do mv $i `echo $i | sed '/orig/new/g'`

I like to do this with sed. In you case:

for x in DET01-*.dat; do
    echo $x | sed -r 's/DET01-ABC-(.+)\.dat/mv -v "\0" "DET01-XYZ-\1.dat"/'
done | sh -e

It is best to omit the "sh -e" part first to see what will be executed.


for file in *.dat ; do mv $file ${file//ABC/XYZ} ; done

No rename or sed needed. Just bash parameter expansion.


All of these answers are simple and good. However, I always like to add an interactive mode to these scripts so that I can find false positives.

if [[ -n $inInteractiveMode ]]
then
  echo -e -n "$oldFileName => $newFileName\nDo you want to do this change? [Y/n]: "
  read run

  [[ -z $run || "$run" == "y" || "$run" == "Y" ]] && mv "$oldFileName" "$newFileName"
fi

Or make interactive mode the default and add a force flag (-f | --force) for automated scripts or if you're feeling daring. And this doesn't slow you down too much: the default response is "yes, I do want to rename" so you can just hit the enter key at each prompt (because of the ``-z $run\ test.


Something like this will do it. The for loop may need to be modified depending on which filenames you wish to capture.

for fspec1 in DET01-ABC-5_50-*.dat ; do
    fspec2=$(echo ${fspec1} | sed 's/-ABC-/-XYZ-/')
    mv ${fspec1} ${fspec2}
done

You should always test these scripts on copies of your data, by the way, and in totally different directories.


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