Normally LIKE statement is used to check the pattern like data.
example:
select * from table1 where name like 'ar%'
My problem is to use one column of table with LIKE statement.
example:
select * from table1, table2 where table1.x is like table2.y%
Query above results error . how to use one column data in like query?
You're close.
The LIKE operator works with strings (CHAR, NVARCHAR, etc). so you need to concattenate the '%' symbol to the string...
MS SQL Server:
SELECT * FROM table1,table2 WHERE table1.x LIKE table2.y + '%'
Use of LIKE, however, is often slower than other operations. It's useful, powerful, flexible, but has performance considerations. I'll leave those for another topic though :)
EDIT:
I don't use MySQL, but this may work...
SELECT * FROM table1,table2 WHERE table1.x LIKE CONCAT(table2.y, '%')
For SQLLite you will need to concat the strings
select * from list1 l, list2 ll
WHERE l.name like "%"||ll.alias||"%";
declare @LkeVal as Varchar(100)
declare @LkeSelect Varchar(100)
Set @LkeSelect = (select top 1 <column> from <table> where <column> = 'value')
Set @LkeVal = '%' + @LkeSelect
select * from <table2> where <column2> like(''+@LkeVal+'');
ORACLE DATABASE example:
select *
from table1 t1, table2 t2
WHERE t1.a like ('%' || t2.b || '%')
SQL SERVER
WHERE ColumnName LIKE '%'+ColumnName+'%'
...
WHERE table1.x LIKE table2.y + '%'
Source: Stackoverflow.com