For some reason my javascript code is messed up. When run through firebug, I get the error proceedToSecond not defined, but it is defined!
JavaScript:
<script type = "text/javascript">
function proceedToSecond () {
document.getElementById("div1").style.visibility="hidden";
document.getElementById("div2").style.visibility="visible";
}
function reset_Form() {
document.personalInfo.reset();
}
function showList() {
alert("hey");
if (document.getElementsById("favSports").style.visibility=="hidden") {
document.getElementsById("favSports").style.visibility="visible");
}
}
//function showList2() {
//}
</script>
HTML:
<body>
<!--various code -->
<input type="button" onClick="proceedToSecond()" value="Proceed to second form"/>
</body>
This question is related to
javascript
html
forms
There are a couple of things to check:
proceedToSecond" into the FireBug console to see if the function gets definedscript tag: it should be <script type="text/javascript"> instead of <script type = "text/javascript">important: in this kind of error you should look for simple mistakes in most cases
besides syntax error, I should say once I had same problem and it was because of bad name I have chosen for function. I have never searched for the reason but I remember that I copied another function and change it to use. I add "1" after the name to changed the function name and I got this error.
I just went through the same problem. And found out once you have a syntax or any type of error in you javascript, the whole file don't get loaded so you cannot use any of the other functions at all.
The actual problem is with your
showList function.
There is an extra ')' after 'visible'.
Remove that and it will work fine.
function showList()
{
if (document.getElementById("favSports").style.visibility == "hidden")
{
// document.getElementById("favSports").style.visibility = "visible");
// your code
document.getElementById("favSports").style.visibility = "visible";
// corrected code
}
}
Source: Stackoverflow.com