How to do an Integer parseInt for a decimal number

Question

The Java code is as follows   String s    0 01   int i   Integer parseInt s     However this is throwing a NumberFormatException    What could be going wrong

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Use   String s  0 01   int i  new Double s  intValue

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0 01 is not an integer  whole number   so you of course can t parse it as one  Use Double parseDouble or Float parseFloat instead

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use this one  int number    int  Double parseDouble s

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suppose we take a integer in string       String s  100         int i Integer parseInt s         or       int i Integer valueOf s        but in your question the number you are trying to do the change is the whole number      String s  10 00        double d Double parseDouble s        int i  int d    This way you get the answer of the value which you are trying to get it

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Using BigDecimal to get rounding   String s1  0 01   int i1   new BigDecimal s1  setScale 0  RoundingMode HALF UP  intValueExact     String s2  0 5   int i2   new BigDecimal s2  setScale 0  RoundingMode HALF UP  intValueExact

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String s  0 01   int i   Double valueOf s  intValue

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This kind of conversion is actually suprisingly unintuitive in Java  Take for example a following string    100 00   C   a simple standard library function at least since 1971  Where did the name  atoi  come from    int i   atoi decimalstring     Java   mandatory passage by Double  or Float  parse  followed by a cast  int i    int Double parseDouble decimalstring     Java sure has some oddities up it s sleeve

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One more solution is possible  int number   Integer parseInt new DecimalFormat  quot   quot   format decimalNumber      Example  Integer parseInt new DecimalFormat  quot   quot   format Double parseDouble  quot 010 021 quot        Output 10

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String s    0 01   double d   Double parseDouble s   int i    int  d    The reason for the exception is that an integer does not hold rational numbers    basically fractions   So  trying to parse 0 3 to a int is nonsense  A double or a float datatype can hold rational numbers   The way Java casts a double to an int is done by removing the part after the decimal separator by rounding towards zero   int i    int  0 9999    i will be zero

User · Answer

Use Double parseDouble String a  what you are looking for is not an integer as it is  not a whole number

[java] How to do an Integer.parseInt() for a decimal number?

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