[c] Printing chars and their ASCII-code in C

How do I print a char and its equivalent ASCII value in C?

Simplest approach in printing ASCII values of a given alphabet.

Here is an example :

#include<stdio.h>
int main()
{
    //we are printing the ASCII value of 'a'
    char a ='a'
    printf("%d",a)
    return 0;
}

Try this:

char c = 'a'; // or whatever your character is
printf("%c %d", c, c);

The %c is the format string for a single character, and %d for a digit/integer. By casting the char to an integer, you'll get the ascii value.

Nothing can be more simple than this

#include <stdio.h>  

int main()  
{  
    int i;  

    for( i=0 ; i<=255 ; i++ ) /*ASCII values ranges from 0-255*/  
    {  
        printf("ASCII value of character %c = %d\n", i, i);  
    }  

    return 0;  
}   

Source: program to print ASCII value of all characters

This reads a line of text from standard input and prints out the characters in the line and their ASCII codes:

#include <stdio.h>

void printChars(void)
{
    unsigned char   line[80+1];
    int             i;

    // Read a text line
    if (fgets(line, 80, stdin) == NULL)
        return;

    // Print the line chars
    for (i = 0;  line[i] != '\n';  i++)
    {
        int     ch;

        ch = line[i];
        printf("'%c' %3d 0x%02X\n", ch, ch, (unsigned)ch);
    }
}

To print all the ascii values from 0 to 255 using while loop.

#include<stdio.h>

int main(void)
{
    int a;
    a = 0;
    while (a <= 255)
    {
        printf("%d = %c\n", a, a);
        a++;
    }
    return 0;
}

#include<stdio.h>
 void main()
{
char a;
scanf("%c",&a);
printf("%d",a);
}

Chars within single quote ('XXXXXX'), when printed as decimal should output its ASCII value.

int main(){

    printf("D\n");
    printf("The ASCII of D is %d\n",'D');

    return 0;

}

Output:

% ./a.out
>> D
>> The ASCII of D is 68