What happens to a declared uninitialized variable in C Does it have a value

Question

If in C I write   int num    Before I assign anything to num  is the value of num indeterminate

User · Answer

That depends  If that definition is global  outside any function  then num will be initialized to zero  If it s local  inside a function  then its value is indeterminate  In theory  even attempting to read the value has undefined behavior -- C allows for the possibility of bits that don t contribute to the value  but have to be set in specific ways for you to even get defined results from reading the variable

User · Answer

Static variables  file scope and function static  are initialized to zero  int x     zero int y   0     also zero  void foo         static int x     also zero    Non-static variables  local variables  are indeterminate  Reading them prior to assigning a value results in undefined behavior  void foo         int x      printf  quot  d quot   x      the compiler is free to crash here    In practice  they tend to just have some nonsensical value in there initially - some compilers may even put in specific  fixed values to make it obvious when looking in a debugger - but strictly speaking  the compiler is free to do anything from crashing to summoning demons through your nasal passages  As for why it s undefined behavior instead of simply  quot undefined arbitrary value quot   there are a number of CPU architectures that have additional flag bits in their representation for various types  A modern example would be the Itanium  which has a  quot Not a Thing quot  bit in its registers  of course  the C standard drafters were considering some older architectures  Attempting to work with a value with these flag bits set can result in a CPU exception in an operation that really shouldn t fail  eg  integer addition  or assigning to another variable   And if you go and leave a variable uninitialized  the compiler might pick up some random garbage with these flag bits set - meaning touching that uninitialized variable may be deadly

User · Answer

The basic answer is  yes it is undefined   If you are seeing odd behavior because of this  it may depended on where it is declared   If within a function on the stack then the contents will more than likely be different every time the function gets called   If it is a static or module scope it is undefined but will not change

User · Answer

Ubuntu 15 10  Kernel 4 2 0  x86-64  GCC 5 2 1 example  Enough standards  let s look at an implementation  -   Local variable  Standards  undefined behavior   Implementation  the program allocates stack space  and never moves anything to that address  so whatever was there previously is used    include  lt stdio h gt  int main         int i      printf   d n   i       compile with   gcc -O0 -std c99 a c   outputs   0   and decompiles with   objdump -dr a out   to   0000000000400536  lt main gt     400536        55                      push    rbp   400537        48 89 e5                mov     rsp  rbp   40053a        48 83 ec 10             sub     0x10  rsp   40053e        8b 45 fc                mov    -0x4  rbp   eax   400541        89 c6                   mov     eax  esi   400543        bf e4 05 40 00          mov     0x4005e4  edi   400548        b8 00 00 00 00          mov     0x0  eax   40054d        e8 be fe ff ff          callq  400410  lt printf plt gt    400552        b8 00 00 00 00          mov     0x0  eax   400557        c9                      leaveq   400558        c3                      retq   From our knowledge of x86-64 calling conventions     rdi is the first printf argument  thus the string   d n  at address 0x4005e4  rsi is the second printf argument  thus i   It comes from -0x4  rbp   which is the first 4-byte local variable   At this point  rbp is in the first page of the stack has been allocated by the kernel  so to understand that value we would to look into the kernel code and find out what it sets that to   TODO does the kernel set that memory to something before reusing it for other processes when a process dies  If not  the new process would be able to read the memory of other finished programs  leaking data  See  Are uninitialized values ever a security risk    We can then also play with our own stack modifications and write fun things like    include  lt assert h gt   int f         int i   13      return i     int g         int i      return i     int main         f        assert g      13       Local variable in -O3  Implementation analysis at  What does  lt value optimized out gt  mean in gdb   Global variables  Standards  0  Implementation   bss section    include  lt stdio h gt  int i  int main         printf   d n   i      gcc -00 -std c99 a c   compiles to   0000000000400536  lt main gt     400536        55                      push    rbp   400537        48 89 e5                mov     rsp  rbp   40053a        8b 05 04 0b 20 00       mov    0x200b04  rip   eax          601044  lt i gt    400540        89 c6                   mov     eax  esi   400542        bf e4 05 40 00          mov     0x4005e4  edi   400547        b8 00 00 00 00          mov     0x0  eax   40054c        e8 bf fe ff ff          callq  400410  lt printf plt gt    400551        b8 00 00 00 00          mov     0x0  eax   400556        5d                      pop     rbp   400557        c3                      retq   400558        0f 1f 84 00 00 00 00    nopl   0x0  rax  rax 1    40055f        00     601044  lt i gt  says that i is at address 0x601044 and   readelf -SW a out   contains    25   bss              NOBITS          0000000000601040 001040 000008 00  WA  0   0  4   which says 0x601044 is right in the middle of the  bss section  which starts at 0x601040 and is 8 bytes long   The ELF standard then guarantees that the section named  bss is completely filled with of zeros       bss This section holds uninitialized data that contribute to the   program   s memory image   By definition  the system initializes the   data with zeros when the program begins to run   The section occu-   pies no file space  as indicated by the section type  SHT NOBITS    Furthermore  the type SHT NOBITS is efficient and occupies no space on the executable file      sh size This member gives the section   s size in bytes   Unless the sec-   tion type is SHT NOBITS   the section occupies sh size   bytes in the file   A section of type SHT NOBITS may have a non-zero   size  but it occupies no space in the file    Then it is up to the Linux kernel to zero out that memory region when loading the program into memory when it gets started

User · Answer

The Value of num will be some garbage value from the main memory RAM   its better if you initialize the variable just after creating

User · Answer

Because computers have finite storage capacity  automatic variables will typically be held in storage elements  whether registers or RAM  that have previously been used for some other arbitrary purpose   If a such a variable is used before a value has been assigned to it  that storage may hold whatever it held previously  and so the contents of the variable will be unpredictable   As an additional wrinkle  many compilers may keep variables in registers which are larger than the associated types   Although a compiler would be required to ensure that any value which is written to a variable and read back will be truncated and or sign-extended to its proper size  many compilers will perform such truncation when variables are written and expect that it will have been performed before the variable is read   On such compilers  something like   uint16 t hey uint32 t x  uint32 t mode    uint16 t q     if  mode  1  q 2     if  mode  3  q 4     return q      uint32 t wow uint32 t mode       return hey 1234567  mode        might very well result in wow   storing the values 1234567 into registers 0 and 1  respectively  and calling foo     Since x isn t needed within  foo   and since functions are supposed to put their return value into register 0  the compiler may allocate register 0 to q   If mode is 1 or 3  register 0 will be loaded with 2 or 4  respectively  but if it is some other value  the function may return whatever was in register 0  i e  the value 1234567  even though that value is not within the range of uint16 t   To avoid requiring compilers to do extra work to ensure that uninitialized variables never seem to hold values outside their domain  and avoid needing to specify indeterminate behaviors in excessive detail  the Standard says that use of uninitialized automatic variables is Undefined Behavior   In some cases  the consequences of this may be even more surprising than a value being outside the range of its type   For example  given   void moo int mode      if  mode  lt  5      launch nukes      hey 0  mode             a compiler could infer that because invoking moo   with a mode which is greater than 3 will inevitably lead to the program invoking Undefined Behavior  the compiler may omit any code which would only be relevant if mode is 4 or greater  such as the code which would normally prevent the launch of nukes in such cases   Note that neither the Standard  nor modern compiler philosophy  would care about the fact that the return value from  hey  is ignored--the act of trying to return it gives a compiler unlimited license to generate arbitrary code

User · Answer

As far as i had gone it is mostly depend on compiler but in general most cases the value is pre assumed as 0 by the compliers  I got garbage value in case of VC   while TC gave value as 0  I Print it like below  int i  printf   d  i

User · Answer

It depends on the storage duration of the variable  A variable with static storage duration is always implicitly initialized with zero   As for automatic  local  variables  an uninitialized variable has indeterminate value  Indeterminate value  among other things  mean that whatever  value  you might  see  in that variable is not only unpredictable  it is not even guaranteed to be stable  For example  in practice  i e  ignoring the UB for a second  this code   int num  int a   num  int b   num    does not guarantee that variables a and b will receive identical values  Interestingly  this is not some pedantic theoretical concept  this readily happens in practice as consequence of optimization   So in general  the popular answer that  it is initialized with whatever garbage was in memory  is not even remotely correct  Uninitialized variable s behavior is different from that of a variable initialized with garbage

User · Answer

0 if static or global  indeterminate if storage class is auto  C has always been very specific about the initial values of objects  If global or static  they will be zeroed  If auto  the value is indeterminate   This was the case in pre-C89 compilers and was so specified by K amp R and in DMR s original C report   This was the case in C89  see section 6 5 7 Initialization      If an object that has automatic   storage duration is not initialized   explicitely  its value is   indeterminate  If an object that has   static storage duration is not   initialized explicitely  it is   initialized implicitely as if every   member that has arithmetic type were   assigned 0 and every member that has   pointer type were assigned a null   pointer constant    This was the case in C99  see section 6 7 8 Initialization      If an object that has automatic   storage duration is not initialized   explicitly  its value is   indeterminate  If an object that has   static storage duration is not   initialized explicitly  then      if it   has pointer type  it is initialized to   a null pointer      if it has arithmetic   type  it is initialized to  positive   or unsigned  zero      if it is an   aggregate  every member is initialized    recursively  according to these   rules      if it is a union  the first   named member is initialized    recursively  according to these   rules    As to what exactly indeterminate means  I m not sure for C89  C99 says      3 17 2 indeterminate valueeither an unspecified value or a trap   representation   But regardless of what standards say  in real life  each stack page actually does start off as zero  but when your program looks at any auto storage class values  it sees whatever was left behind by your own program when it last used those stack addresses  If you allocate a lot of auto arrays you will see them eventually start neatly with zeroes   You might wonder  why is it this way   A different SO answer deals with that question  see  https   stackoverflow com a 2091505 140740

User · Answer

If storage class is static or global then during loading  the BSS  initialises the variable or memory location ML  to 0 unless the variable is initially assigned some value  In case of local uninitialized variables the trap representation is assigned to memory location  So if any of your registers containing important info is overwritten by compiler the program may crash   but some compilers may have mechanism to avoid such a problem   I was working with nec v850 series when i realised There is trap representation which has bit patterns that represent undefined values for data types except for char  When i took a uninitialized char i got a zero default value due to trap representation  This might be useful for any1 using necv850es

[c] What happens to a declared, uninitialized variable in C? Does it have a value?

Examples related to c

Examples related to initialization

Examples related to declaration