Cannot use string offset as an array in php

Question

I m trying to simulate this error with a sample php code but haven t been successful  Any help would be great    Cannot use string offset as an array

User · Answer

When you directly print print r   value   lt YOUR ARRAY gt   - gt  lt YOUR OBJECT gt     then it shows this fatal error Cannot use string offset as an object in  If you print like this    var    value   node  - gt  lt YOU OBJECT gt   print r  var    You won t get the error

User · Answer

I was able to reproduce this once I upgraded to PHP 7  It breaks when you try to force array elements into a string    params       foreach   foo       index   0     params  index   keyName      name          fileExt      After changing     params         to    params   array      I stopped getting the error  I found the solution in this bug report thread  I hope this helps

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I had this error for the first time ever while trying to debug some old legacy code  running now on PHP 7 30  The simplified code looked like this    testOK   true   if   testOK         x  error       0       x  size       10       x  type        file        x  tmp name        path to file        The simplest fix possible was to declare  x as array   before    x   array     if   testOK           same code

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The error occurs when    a   array      a  text1     array     a  text1    text2      sometext     Then   echo  a  text1    text2          Error     Solution   b    a  text1    echo  b  text2          prints  sometext

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I was fighting a similar problem  so documenting here in case useful   In a   get   method I was using the given argument as a property  as in  simplified example    function   get  prop         return  this- gt  prop         i e   obj- gt fred would access the private protected fred property of the class   I found that when I needed to reference an array structure within this property it generated the Cannot use String offset as array error  Here s what I did wrong and how to correct it   function   get  prop            this is wrong  generates the error      return  this- gt  prop  some key   0      function   get  prop            this is correct       ref    amp   this- gt  prop       return  ref  some key   0       Explanation  in the wrong example  php is interpreting   some key   as a key to  prop  a string   whereas we need it to dereference  prop in place  In Perl you could do this by specifying with    but I don t think this is possible in PHP

User · Answer

I just want to explain my solving for the same problem   my code before given same error     arr2         this is the problem and solve by replace this  arr2   array    for  i 2  i lt count  arrdata   i          rowx   explode      arrdata  i         arr1         and this is too     for  x 0  x lt count  rowx   x             if  rowx  x                     arr1      rowx  x                        arr2      arr1    for  i 0  i lt count  arr2   i          td     lt tr gt        for  j 0  j lt count  hcol -1  j              td      lt td style  border-right 0px solid  000  gt    arr2  i   j    lt  td gt      and it s  arr2  i   j   give an error  Cannot use string offset as an array            td     lt  tr gt        my code after and solved it    arr2  array      change this from  arr2     for  i 2  i lt count  arrdata   i          rowx   explode      arrdata  i         arr1 array      and this     for  x 0  x lt count  rowx   x             if  rowx  x                     arr1      rowx  x                        arr2      arr1    for  i 0  i lt count  arr2   i          td     lt tr gt        for  j 0  j lt count  hcol -1  j              td      lt td style  border-right 0px solid  000  gt    arr2  i   j    lt  td gt               td     lt  tr gt        Thank s  Hope it s helped  and sorry if my english mess like boy s room  D

User · Answer

I believe what are you asking about is a variable interpolation in PHP   Let s do a simple fixture    obj    object  array  foo    gt  array  bar     property    gt   value     var    foo     Now we have an object  where   print r  obj     Will give output   stdClass Object                foo    gt  Array                                0    gt  bar                         property    gt  value         And we have variable  var containing string  foo    If you ll try to use    give me foo    obj- gt  var 0     Instead of    give me foo    obj- gt foo 0     You get  Cannot use string offset as an array        error message as a result  because what you are trying to do  is in fact sending message  var 0  to object  obj  And - as you can see from fixture - there is no content of  var 0  defined  Variable  var is a string and not an array   What you can do in this case is to use curly braces  which will assure that at first is called content of  var  and subsequently the rest of message-sent    give me foo    obj- gt   var  0     The result is  bar   as you would expect

User · Answer

For PHP4     this reproduced the error    foo       bar    foo 0     bar     For PHP5     this reproduced the error    foo    bar    if  is array  foo  bar         echo  bar-array   if  is array  foo  bar    foo         echo  bar-foo-array   if  is array  foo  bar    foo    bar         echo  bar-foo-bar-array      From bugs php net actually   Edit      so why doesn t the error appear in the   first if condition even though it is a   string    Because PHP is a very forgiving programming language  I d guess  I ll illustrate with code of what I think is going on    foo    bar       foo is now equal to  bar    foo  bar      foo       foo  bar   doesn t exists - use first index instead  0      foo  bar   is equal to using  foo 0      foo  bar   points to a character so the string  foo  won t fit     foo  bar   will instead be set to the first index    of the string array  foo   i e  f   echo  foo  bar       output will be  f   echo  foo     output will be  far   echo  foo  bar    bar        foo  bar   0  is equal calling to  foo  bar    bar       foo  bar   points to a character    characters can not be represented as an array     so we cannot reach anything at position 0 of a character    -- gt  fatal error

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Since the release PHP 7 1   is not more possible to assign a value for an array as follow   foo    quot  quot     foo  key      foo2    because as of PHP 7 1 0  applying the empty index operator on a string throws a fatal error  Formerly  the string was silently converted to an array

User · Answer

I was having this error and a was nuts  my code was   aux users      foreach   usuarios  a   as  iterador      code if   is numeric  consultores 0 - gt ganancia           aux users  iterador   ganancia   round  consultores 0 - gt ganancia 2           after changing  aux users     to  aux users array     it happen to my in php 7 2  in production server   but was working on php 5 6 and php 7 0 30 so be aware  and thanks to Young Michael  i hope it helps you too

[php] Cannot use string offset as an array in php

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