[regex] What regular expression will match valid international phone numbers?

I need to determine whether a phone number is valid before attempting to dial it. The phone call can go anywhere in the world.

What regular expression will match valid international phone numbers?

This will work for international numbers;

C#:

@"^((\+\d{1,3}(-| )?\(?\d\)?(-| )?\d{1,5})|(\(?\d{2,6}\)?))(-| )?(\d{3,4})(-| )?(\d{4})(( x| ext)\d{1,5}){0,1}$"

JS:

/^((\+\d{1,3}(-| )?\(?\d\)?(-| )?\d{1,5})|(\(?\d{2,6}\)?))(-| )?(\d{3,4})(-| )?(\d{4})(( x| ext)\d{1,5}){0,1}$/

There's obviously a multitude of ways to do this, as evidenced by all of the different answers given thus far, but I'll throw my $0.02 worth in here and provide the regex below, which is a bit more terse than nearly all of the above, but more thorough than most as well. It also has the nice side-effect of leaving the country code in $1 and the local number in $2.

^\+(?=\d{5,15}$)(1|2[078]|3[0-469]|4[013-9]|5[1-8]|6[0-6]|7|8[1-469]|9[0-58]|[2-9]..)(\d+)$

It works pretty well with 00xx and +xx:

^(?:00|\+)(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|4[987654310]|3[9643210]|2[70]|7|1)\d{1,14}$

public static boolean validateInternationalPhoneNumberFormat(String phone) {
    StringBuilder sb = new StringBuilder(200);

    // Country code
    sb.append("^(\\+{1}[\\d]{1,3})?");

    // Area code, with or without parentheses
    sb.append("([\\s])?(([\\(]{1}[\\d]{2,3}[\\)]{1}[\\s]?)|([\\d]{2,3}[\\s]?))?");

    // Phone number separator can be "-", "." or " "

    // Minimum of 5 digits (for fixed line phones in Solomon Islands)
    sb.append("\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?");

    // 4 more optional digits
    sb.append("\\d?[\\-\\.\\s]?\\d?[\\-\\.\\s]?\\d?[\\-\\.\\s]?\\d?$");

    return Pattern.compile(sb.toString()).matcher(phone).find();
}

A simple version for european numbers, that matches numbers like 0034617393211 but also long ones as 004401484172842.

^0{2}[0-9]{11,}

Hope it helps :·)

Here is a regex for the following most common phone number scenarios. Although this is tailored from a US perspective for area codes it works for international scenarios.

1. The actual number should be 10 digits only.
2. For US numbers area code may be surrounded with parentheses ().
3. The country code can be 1 to 3 digits long. Optionally may be preceded by a + sign.
4. There may be dashes, spaces, dots or no spaces between country code, area code and the rest of the number.

5. A valid phone number cannot be all zeros.

   ^(?!\b(0)\1+\b)(\+?\d{1,3}[. -]?)?\(?\d{3}\)?([. -]?)\d{3}\3\d{4}$
   

Explanation:

    ^ - start of expression  
    (?!\b(0)\1+\b) - (?!)Negative Look ahead. \b - word boundary around a '0' character. \1 backtrack to previous capturing group (zero). Basically don't match all zeros.  
    (\+?\d{1,3}[. -]?)? - '\+?' plus sign before country code is optional.\d{1,3} - country code can be 1 to 3 digits long. '[. -]?' - spaces,dots and dashes are optional. The last question mark is to make country code optional.  
    \(?\d{3}\)? - '\)?' is to make parentheses optional. \d{3} - match 3 digit area code.  
    ([. -]?) - optional space, dash or dot
    $ - end of expression

More examples and explanation - https://regex101.com/r/hTH8Ct/2/

For iOS SWIFT I found this helpful,

let phoneRegEx = "^((\\+)|(00)|(\\*)|())[0-9]{3,14}((\\#)|())$"

I use this one:

/([0-9\s\-]{7,})(?:\s*(?:#|x\.?|ext\.?|extension)\s*(\d+))?$/

Advantages: recognizes + or 011 beginnings, lets it be as long as needed, and handles many extension conventions. (#,x,ext,extension)

No criticism regarding those great answers I just want to present the simple solution I use for our admin content creators:

^(\+|00)[1-9][0-9 \-\(\)\.]{7,}$

Force start with a plus or two zeros and use at least a little bit of numbers, white space, braces, minus and point is optional and no other characters. You can safely remove all non-numbers and use this in a tel: input. Numbers will have a common form of representation and I do not have to worry about being to restrictive.

Try the following API for phone number validation. Also this will return the Country, Area and Provider

demo https://libphonenumber.appspot.com/

git https://github.com/googlei18n/libphonenumber/releases/tag/v8.9.0

Try this, I do not know if there is any phone number longer than 12:

^(00|\+){1}\d{12}$

The international numbering plan is based on the ITU E.164 numbering plan. I guess that's the starting point to your regular expression.

I'll update this if I get around to create a regular expression based on the ITU E.164 numbering.

All country codes are defined by the ITU. The following regex is based on ITU-T E.164 and Annex to ITU Operational Bulletin No. 930 – 15.IV.2009. It contains all current country codes and codes reserved for future use. While it could be shortened a bit, I decided to include each code independently.

This is for calls originating from the USA. For other countries, replace the international access code (the 011 at the beginning of the regex) with whatever is appropriate for that country's dialing plan.

Also, note that ITU E.164 defines the maximum length of a full international telephone number to 15 digits. This means a three digit country code results in up to 12 additional digits, and a 1 digit country code could contain up to 14 additional digits. Hence the

[0-9]{0,14}$

a the end of the regex.

Most importantly, this regex does not mean the number is valid - each country defines its own internal numbering plan. This only ensures that the country code is valid.

^011(999|998|997|996|995|994|993|992|991| 990|979|978|977|976|975|974|973|972|971|970| 969|968|967|966|965|964|963|962|961|960|899| 898|897|896|895|894|893|892|891|890|889|888| 887|886|885|884|883|882|881|880|879|878|877| 876|875|874|873|872|871|870|859|858|857|856| 855|854|853|852|851|850|839|838|837|836|835| 834|833|832|831|830|809|808|807|806|805|804| 803|802|801|800|699|698|697|696|695|694|693| 692|691|690|689|688|687|686|685|684|683|682| 681|680|679|678|677|676|675|674|673|672|671| 670|599|598|597|596|595|594|593|592|591|590| 509|508|507|506|505|504|503|502|501|500|429| 428|427|426|425|424|423|422|421|420|389|388| 387|386|385|384|383|382|381|380|379|378|377| 376|375|374|373|372|371|370|359|358|357|356| 355|354|353|352|351|350|299|298|297|296|295| 294|293|292|291|290|289|288|287|286|285|284| 283|282|281|280|269|268|267|266|265|264|263| 262|261|260|259|258|257|256|255|254|253|252| 251|250|249|248|247|246|245|244|243|242|241| 240|239|238|237|236|235|234|233|232|231|230| 229|228|227|226|225|224|223|222|221|220|219| 218|217|216|215|214|213|212|211|210|98|95|94| 93|92|91|90|86|84|82|81|66|65|64|63|62|61|60| 58|57|56|55|54|53|52|51|49|48|47|46|45|44|43| 41|40|39|36|34|33|32|31|30|27|20|7|1)[0-9]{0, 14}$

This Regex Expression works for India, Canada, Europe, New Zealand, Australia, United States phone numbers, along with their country codes:

"^(\+(([0-9]){1,2})[-.])?((((([0-9]){2,3})[-.]){1,2}([0-9]{4,10}))|([0-9]{10}))$"

I made the regexp for european phone numbers, and it is specific against dial prefix vs length of number.

const PhoneEuropeRegExp = () => {
    // eu phones map https://en.wikipedia.org/wiki/Telephone_numbers_in_Europe
    const phonesMap = {
        "43": [4, 13],
        "32": [8, 10],
        "359": [7, 9],
        "385": [8, 9],
        "357": 8,
        "420": 9,
        "45": 8,
        "372": 7,
        "358": [5, 12],
        "33": 9,
        "350": 8,
        "49": [3, 12],
        "30": 10,
        "36": [8, 9],
        "354": [7, 9],
        "353": [7, 9],
        "39": [6, 12],
        "371": 8,
        "423": [7, 12],
        "370": 8,
        "352": 8,
        "356": 8,
        "31": 9,
        "47": [4, 12],
        "48": 9,
        "351": 9,
        "40": 9,
        "421": 9,
        "386": 8,
        "34": 9,
        "46": [6, 9],
    };
    const regExpBuilt = Object.keys(phonesMap)
        .reduce(function(prev, key) {
            const val = phonesMap[key];
            if (Array.isArray(val)) {
                prev.push("(\\+" + key + `[0-9]\{${val[0]},${val[1]}\})`);
            } else {
                prev.push("(\\+" + key + `[0-9]\{${val}\})`);
            }
            return prev;
        }, [])
        .join("|");
    return new RegExp(`^(${regExpBuilt})$`);
};

alert(PhoneEuropeRegExp().test("+420123456789"))

Try this, it works for me.

^(00|\+)[1-9]{1}([0-9][\s]*){9,16}$

You can use the library libphonenumber from Google.

PhoneNumberUtil phoneNumberUtil = PhoneNumberUtil.getInstance();
String decodedNumber = null;
PhoneNumber number;
    try {
        number = phoneNumberUtil.parse(encodedHeader, null);
        decodedNumber = phoneNumberUtil.format(number, PhoneNumberFormat.E164);
    } catch (NumberParseException e) {
        e.printStackTrace();
    }

Even though this is not really using RegExp to get the job done - or maybe because of that - this looks like a nice solution to me: https://intl-tel-input.com/node_modules/intl-tel-input/examples/gen/is-valid-number.html

This works for me, without 00, 001, 0011 etc prefix though:

/^\+*(\d{3})*[0-9,\-]{8,}/

I have used this below:

^(\+|00)[0-9]{1,3}[0-9]{4,14}(?:x.+)?$

The format +CCC.NNNNNNNNNNxEEEE or 00CCC.NNNNNNNNNNxEEEE

Phone number must start with '+' or '00' for an international call. where C is the 1–3 digit country code,

N is up to 14 digits,

and E is the (optional) extension.

The leading plus sign and the dot following the country code are required. The literal “x” character is required only if an extension is provided.

This is a further optimisation.

\+(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)
\W*\d\W*\d\W*\d\W*\d\W*\d\W*\d\W*\d\W*\d\W*(\d{1,2})$

(i) allows for valid international prefixes
(ii) followed by 9 or 10 digits, with any type or placing of delimeters (except between the last two digits)

This will match:
+1-234-567-8901
+61-234-567-89-01
+46-234 5678901
+1 (234) 56 89 901
+1 (234) 56-89 901
+46.234.567.8901
+1/234/567/8901

Here's an "optimized" version of your regex:

^011(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\d{0,14}$

You can replace the \ds with [0-9] if your regex syntax doesn't support \d.

Modified @Eric's regular expression - added a list of all country codes (got them from xxxdepy @ Github. I hope you will find it helpful:

/(\+|00)(297|93|244|1264|358|355|376|971|54|374|1684|1268|61|43|994|257|32|229|226|880|359|973|1242|387|590|375|501|1441|591|55|1246|673|975|267|236|1|61|41|56|86|225|237|243|242|682|57|269|238|506|53|5999|61|1345|357|420|49|253|1767|45|1809|1829|1849|213|593|20|291|212|34|372|251|358|679|500|33|298|691|241|44|995|44|233|350|224|590|220|245|240|30|1473|299|502|594|1671|592|852|504|385|509|36|62|44|91|246|353|98|964|354|972|39|1876|44|962|81|76|77|254|996|855|686|1869|82|383|965|856|961|231|218|1758|423|94|266|370|352|371|853|590|212|377|373|261|960|52|692|389|223|356|95|382|976|1670|258|222|1664|596|230|265|60|262|264|687|227|672|234|505|683|31|47|977|674|64|968|92|507|64|51|63|680|675|48|1787|1939|850|351|595|970|689|974|262|40|7|250|966|249|221|65|500|4779|677|232|503|378|252|508|381|211|239|597|421|386|46|268|1721|248|963|1649|235|228|66|992|690|993|670|676|1868|216|90|688|886|255|256|380|598|1|998|3906698|379|1784|58|1284|1340|84|678|681|685|967|27|260|263)(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|4[987654310]|3[9643210]|2[70]|7|1)\d{4,20}$/