Linux Shell Script For Each File in a Directory Grab the filename and execute a program

Question

Scenario    A folder in Linux system  I want to loop through every  xls file in a folder   This folder typically consists of various folders  various filetypes   sh   pl  csv        All I want to do is loop through all files in the root and execute a program only on  xls files   Edit    The problem is the program I have to execute is  xls2csv  to convert from  xls to  csv format  So  for each  xls file I have to grab the filename and append it to  csv    For instance  I have a test xls file and the arguments fro xls2csv are   xls2csv test xls test csv   Did I make sense

User · Answer

Look at the find command   What you are looking for is something like  find   -name    xls  -type f -exec program    Post edit  find   -name    xls  -type f -exec xls2csv           csv    will execute  xls2csv file xls file xls csv  Closer to what you want

User · Answer

for i in   xls   do       -f   i        continue   xls2csv   i     i  xls  csv  done   The first line in the do checks if the  matching  file really exists  because in case nothing matches in your for  the do will be executed with    xls  as  i  This could be horrible for your xls2csv

User · Answer

find   -type f -name    xls  -printf  xls2csv  p  p csv n    bash   bash 4  recursive   shopt -s globstar for xls in  path      xls do   xls2csv   xls     xls  xls  csv  done

User · Answer

bash   for f in   xls   do xls2csv   f     f  xls  csv    done

[linux] Linux Shell Script For Each File in a Directory Grab the filename and execute a program

Examples related to linux

Examples related to shell