With C++11, you don't even need the length/size. As long as the string is not empty, you can do the following:
if (!st.empty())
st.erase(std::prev(st.end())); // Erase element referred to by iterator one
// before the end
If the length is non zero, you can also
str[str.length() - 1] = '\0';
str.erase(str.begin() + str.size() - 1)
str.erase(str.rbegin())
does not compile unfortunately, since reverse_iterator
cannot be converted to a normal_iterator.
C++11 is your friend in this case.
int main () {
string str1="123";
string str2 = str1.substr (0,str1.length()-1);
cout<<str2; // output: 12
return 0;
}
That's all you need:
#include <string> //string::pop_back & string::empty
if (!st.empty())
st.pop_back();
if (str.size () > 0) str.resize (str.size () - 1);
An std::erase alternative is good, but I like the "- 1" (whether based on a size or end-iterator) - to me, it helps expresses the intent.
BTW - Is there really no std::string::pop_back ? - seems strange.
buf.erase(buf.size() - 1);
This assumes you know that the string is not empty. If so, you'll get an out_of_range
exception.
Simple solution if you are using C++11. Probably O(1) time as well:
st.pop_back();
Source: Stackoverflow.com