Converting an int to a binary string representation in Java

Question

What would be the best way  ideally  simplest  to convert an int to a binary string representation in Java   For example  say the int is 156  The binary string representation of this would be  10011100

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One more way- By using java lang Integer you can get string representation of the first argument i in the radix  Octal - 8  Hex - 16  Binary - 2  specified by the second argument    Integer toString i  radix    Example   private void getStrtingRadix                TODO Auto-generated method stub             returns the string representation of the            unsigned integer in concern radix            System out println  Binary eqivalent of 100       Integer toString 100  2             System out println  Octal eqivalent of 100       Integer toString 100  8             System out println  Decimal eqivalent of 100       Integer toString 100  10             System out println  Hexadecimal eqivalent of 100       Integer toString 100  16            OutPut   Binary eqivalent of 100   1100100 Octal eqivalent of 100   144 Decimal eqivalent of 100   100 Hexadecimal eqivalent of 100   64

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public class Main        public static String toBinary int n  int l   throws Exception          double pow    Math pow 2  l          StringBuilder binary   new StringBuilder            if   pow  lt  n                 throw new Exception  The length must be big from number                      int shift   l- 1         for    shift  gt   0   shift--               int bit    n  gt  gt  shift   amp  1             if  bit    1                   binary append  1                 else                  binary append  0                                 return binary toString              public static void main String   args  throws Exception           System out println   binary       toBinary 7  4            System out println   binary       Integer toString 7 2

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Using bit shift is a little quicker      public static String convertDecimalToBinary int N         StringBuilder binary   new StringBuilder 32        while  N  gt  0             binary append  N   2            N  gt  gt   1              return binary reverse   toString

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Using built-in function   String binaryNum   Integer toBinaryString int num     If you don t want to use the built-in function for converting int to binary then you can also do this   import java util    public class IntToBinary       public static void main String   args            Scanner d   new Scanner System in           int n          n   d nextInt            StringBuilder sb   new StringBuilder            while n  gt  0           int r   n 2          sb append r           n   n 2                    System out println sb reverse

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The simplest approach is to check whether or not the number is odd  If it is  by definition  its right-most binary number will be  1   2 0   After we ve determined this  we bit shift the number to the right and check the same value using recursion    Test public void shouldPrintBinary         StringBuilder sb   new StringBuilder        convert 1234  sb      private void convert int n  StringBuilder sb         if  n  gt  0            sb append n   2           convert n  gt  gt  1  sb         else           System out println sb reverse   toString

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public static string intToBinary int n        String s    quot  quot       while  n  gt  0                s       n   2      0    quot 0 quot     quot 1 quot    s          n   n   2            return s

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public class BinaryConverter        public static String binaryConverter int number            String binary               if  number    1               binary    1               System out print binary               return binary                    if  number    0               binary    0               System out print binary               return binary                    if  number  gt  1                String i   Integer toString number   2                binary   binary   i              binaryConverter number 2                     System out print binary           return binary

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This can be expressed in pseudocode as   while n  gt  0       remainder   n 2      n   n 2      Insert remainder to front of a list or push onto a stack  Print list or stack

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Convert Integer to Binary   import java util Scanner   public class IntegerToBinary        public static void main String   args             Scanner input   new Scanner  System in             System out println  Enter Integer              String integerString  input nextLine             System out println  Binary Number    Integer toBinaryString Integer parseInt integerString                Output   Enter Integer    10  Binary Number  1010

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You can use while loop as well to convert an int to binary  Like this   import java util Scanner   public class IntegerToBinary      public static void main String   args             int num        String str             Scanner sc   new Scanner System in         System out print  Please enter the a number             num   sc nextInt          while num  gt  0                   int y   num   2           str   y   str           num   num   2                System out println  The binary conversion is       str         sc close             Source and reference - convert int to binary in java example

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There is also the java lang Integer toString int i  int base  method  which would be more appropriate if your code might one day handle bases other than 2  binary   Keep in mind that this method only gives you an unsigned representation of the integer i  and if it is negative  it will tack on a negative sign at the front  It won t use two s complement

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This should be quite simple with something like this    public static String toBinary int number       StringBuilder sb   new StringBuilder         if number    0          return  0       while number gt  1           sb append number 2           number   number   2             return sb reverse   toString

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You should really use Integer toBinaryString    as shown above   but if for some reason you want your own      Like Integer toBinaryString  but always returns 32 chars public static String asBitString int value      final char   buf   new char 32     for  int i   31  i  gt   0  i--        buf 31 - i      1  lt  lt  i   amp  value     0    0     1         return new String buf

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This is something I wrote a few minutes ago just messing around  Hope it helps   public class Main    public static void main String   args         ArrayList lt Integer gt  powers   new ArrayList lt Integer gt         ArrayList lt Integer gt  binaryStore   new ArrayList lt Integer gt          powers add 128       powers add 64       powers add 32       powers add 16       powers add 8       powers add 4       powers add 2       powers add 1        Scanner sc   new Scanner System in       System out println  Welcome to Paden9000 binary converter  Please enter an integer you wish to convert          int input   sc nextInt        int printableInput   input       for  int i   powers            if  input  lt  i                binaryStore add 0                  else               input   input - i              binaryStore add 1                                                String newString  binaryStore toString        String finalOutput   newString replace                       replace                       replace                       replace                System out println  Integer value      printableInput     nBinary value      finalOutput       sc close

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Integer toBinaryString int i

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here is my methods  it is a little bit convince that number of bytes fixed  private void printByte int value    String currentBinary   Integer toBinaryString 256   value   System out println currentBinary substring currentBinary length   - 8       public int binaryToInteger String binary    char   numbers   binary toCharArray    int result   0  for int i numbers length - 1  i gt  0  i--    if numbers i    1       result    Math pow 2   numbers length-i - 1    return result

[java] Converting an int to a binary string representation in Java?

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