Rounding a double to turn it into an int java

Question

Right now I m trying this    int a   round n     where n is a double but it s not working  What am I doing wrong

User · Answer

Documentation of Math round says      Returns the result of rounding the argument to an integer  The result   is equivalent to  int  Math floor f 0 5     No need to cast to int  Maybe it was changed from the past

User · Answer

What is the return type of the round   method in the snippet   If this is the Math round   method  it returns a Long when the input param is Double   So  you will have to cast the return value   int a    int  Math round doubleVar

User · Answer

If you don t like Math round   you can use this simple approach as well   int a    int   doubleVar   0 5

User · Answer

import java math    public class TestRound11     public static void main String args         double d   3 1537      BigDecimal bd   new BigDecimal d       bd   bd setScale 2 BigDecimal ROUND HALF UP          output is 3 15     System out println d           round d  2           output is 3 154     System out println d           round d  3           public static double round double d  int decimalPlace          see the Javadoc about why we use a String in the constructor        http   java sun com j2se 1 5 0 docs api java math BigDecimal html BigDecimal double      BigDecimal bd   new BigDecimal Double toString d        bd   bd setScale decimalPlace BigDecimal ROUND HALF UP       return bd doubleValue

User · Answer

You really need to post a more complete example  so we can see what you re trying to do  From what you have posted  here s what I can see  First  there is no built-in round   method  You need to either call Math round n   or statically import Math round  and then call it like you have

User · Answer

Rounding double to the  nearest  integer like this   1 4 -  1  1 6 -  2  -2 1 -  -2  -1 3 -  -1  -1 5 -  -2  private int round double d       double dAbs   Math abs d       int i    int  dAbs      double result   dAbs -  double  i      if result lt 0 5           return d lt 0   -i   i                   else          return d lt 0   - i 1    i 1                      You can change condition  result lt 0 5  as you prefer

User · Answer

public static int round double d        if  d  gt  0            return  int   d   0 5         else           return  int   d - 0 5

User · Answer

The Math round function is overloaded When it receives a float value  it will give you an int  For example this would work   int a Math round 1 7f     When it receives a double value  it will give you a long  therefore you have to typecast it to int   int a  int Math round 1 7     This is done to prevent loss of precision  Your double value is 64bit  but then your int variable can only store 32bit so it just converts it to long  which is 64bit but you can typecast it to 32bit as explained above

[java] Rounding a double to turn it into an int (java)

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