How to concatenate int values in java

Question

I have the following values   int a 1   int b 0  int c 2  int d 2  int e 1    How do i concatenate these values so that i end up with a String that is 10221  please note that multiplying a by 10000  b by 1000     and e by 1 will not working since b 0  and therefore i will lose it when i add the values up

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Assuming you start with variables   int i 12  int j 12    This will give output 1212   System out print i    j      And this will give output 24   System out print i j

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Michael Borgwardt s solution is the best for 5 digits  but if you have variable number of digits  you can use something like this   public static String concatenateDigits int    digits       StringBuilder sb   new StringBuilder digits length      for  int digit   digits         sb append digit           return sb toString

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StringBuffer sb   new StringBuffer    sb append a  append b  append c       Keeping the values as an int is preferred thou  as the other answers show you

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Others have pointed out that multiplying b by 1000 shouldn t cause a problem - but if a were zero  you d end up losing it   You d get a 4 digit string instead of 5    Here s an alternative  general purpose  approach - which assumes that all the values are in the range 0-9   You should quite possibly put in some code to throw an exception if that turns out not to be true  but I ve left it out here for simplicity    public static String concatenateDigits int    digits        char   chars   new char digits length       for  int i   0  i  lt  digits length  i                  chars i     char  digits i     0              return new String chars       In this case you d call it with   String result   concatenateDigits a  b  c  d  e

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If you multiply b by 1000  you will not lose any of the values  See below for the math   10000     0   200    20     1       10221

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Couldn t you just make the numbers strings  concatenate them  and convert the strings to an integer value

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just to not forget the  format method  String s   String format   s s s s s   a  b  c  d  e       1 1s 1 1s 1 1s 1 1s 1 1s if you only want the first digit of each number

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Actually   int result   a   10000   b   1000   c   100   d   10   e  String s   Integer toString result     will work   Note  this will only work when a is greater than 0 and all of b  c  d and e are in  0  9   For example  if b is 15  Michael s method will get you the result you probably  want

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int number  0  int   tab    your numbers    for int i 0  i lt tab length  i         number  10      number  tab i      And you have your concatenated number

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I would suggest converting them to Strings   StringBuilder concatenated   new StringBuilder    concatenated append a   concatenated append b       etc    concatenated append e     Then converting back to an Integer   Integer valueOf concatenated toString

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People were fretting over what happens when a    0   Easy fix for that   have a digit before it       int sum   100000   a 10000   b 1000   c 100   d 10   e  System out println String valueOf sum  substring 1      Biggest drawback   it creates two strings   If that s a big deal  String format could help   int sum   a 10000   b 1000   c 100   d 10   e  System out println String format   05d   sum

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Using Java 8 and higher  you can use the StringJoiner  a very clean and more flexible way  especially if you have a list as input instead of known set of variables a-e    int a   1  int b   0  int c   2  int d   2  int e   1  List lt Integer gt  values   Arrays asList a  b  c  d  e   String result   values stream   map i - gt  i toString    collect Collectors joining     System out println result     If you need a separator use   String result   values stream   map i - gt  i toString    collect Collectors joining          To get the following result      1 0 2 2 1   Edit  as LuCio commented  the following code is shorter   Stream of a  b  c  d  e  map Object  toString  collect Collectors joining

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The easiest  but somewhat dirty  way   String result        a   b   c   d   e   Edit  I don t recommend this and agree with Jon s comment  Adding those extra empty strings is probably the best compromise between shortness and clarity

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This worked for me   int i   14  int j   26  int k   Integer valueOf String valueOf i    String valueOf j    System out println k     It turned out as 1426

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public class joining        public static void main String   args            int a 1           int b 0          int c 2          int d 2          int e 1           String j   Long toString a           String k   Long toString b           String l   Long toString c           String m   Long toString d           String n   Long toString e              String s1 Long toString a         converting long to String         String s2 Long toString b           String s3 s2 s1          long c Long valueOf s3  longValue          converting String to long                     System out println j k l m n

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NOTE  when you try to use   operator on  string   int  it converts int into strings and concatnates them   so you need to convert only one int to string  public class scratch    public static void main String   args        int a 1      int b 0      int c 2      int d 2      int e 1      System out println  String valueOf a  b c d e

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You can Use   String x   a     b      c    d     e  int result   Integer parseInt x

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Best solutions are already discussed  For the heck of it  you could do this as well  Given that you are always dealing with 5 digits    new java util Formatter   format   d d d d d   a b c d e   toString     I am not claiming this is the best way  just adding an alternate way to look at similar situations

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How about not using strings at all     This should work for any number of digits     int   nums    1  0  2  2  1    int retval   0   for  int digit   nums        retval    10      retval    digit     System out println  Return value is      retval

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For fun    how NOT to do it  -   String s   Arrays asList a b c d e  toString   replaceAll                      Not that anyone would really think of doing it this way in this case - but this illustrates why it s important to give access to certain object members  otherwise API users end up parsing the string representation of your object  and then you re stuck not being able to modify it  or risk breaking their code if you do

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Use StringBuilder  StringBuilder sb   new StringBuilder String valueOf a    sb append String valueOf b    sb append String valueOf c    sb append String valueOf d    sb append String valueOf e    System out print sb toString

[java] How to concatenate int values in java?

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