[command-line] How to get a list of sub-folders and their files, ordered by folder-names

How about using sort?

dir /b /s | sort

Here's an example I tested with:


dir /s /b /o:gn

d:\root0
d:\root0\root1
d:\root0\root1\folderA
d:\root0\root1\folderB
d:\root0\root1\file00.txt
d:\root0\root1\file01.txt
d:\root0\root1\folderA\fileA00.txt
d:\root0\root1\folderA\fileA01.txt
d:\root0\root1\folderB\fileB00.txt
d:\root0\root1\folderB\fileB01.txt

dir /s /b | sort

d:\root0
d:\root0\root1
d:\root0\root1\file00.txt
d:\root0\root1\file01.txt
d:\root0\root1\folderA
d:\root0\root1\folderA\fileA00.txt
d:\root0\root1\folderA\fileA01.txt
d:\root0\root1\folderB
d:\root0\root1\folderB\fileB00.txt
d:\root0\root1\folderB\fileB01.txt

To just get directories, use the /A:D parameter:

dir /a:d /s /b | sort

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