i wanted to convert double to float in C, but wanted to preserve the decimal point exactly as possible without any changes...
for example, let's say i have
double d = 0.1108;
double dd = 639728.170000;
double ddd = 345.2345678
now correct me if i am wrong, i know that floating point precision is about 5 numbers after the dot. can i get those five numbers after the dot exactly as the double had it? so that above results as follows:
float f = x(d);
float ff = x(dd);
float fff = x(ddd);
printf("%f\n%f\n%f\n", f, ff, fff);
it should print
0.1108
639728.17000
345.23456
all digits after the precision limit (which i assume as 5) would be truncated.
This question is related to
c
floating-point
double
c89
A float
generally has about 7 digits of precision, regardless of the position of the decimal point. So if you want 5 digits of precision after the decimal, you'll need to limit the range of the numbers to less than somewhere around +/-100.
Floating point numbers are represented in scientific notation as a number of only seven significant digits multiplied by a larger number that represents the place of the decimal place. More information about it on Wikipedia:
Source: Stackoverflow.com