[c++] How can I get the class name from a C++ object?

You could try using "typeid".

This doesn't work for "object" name but YOU know the object name so you'll just have to store it somewhere. The Compiler doesn't care what you namned an object.

Its worth bearing in mind, though, that the output of typeid is a compiler specific thing so even if it produces what you are after on the current platform it may not on another. This may or may not be a problem for you.

The other solution is to create some kind of template wrapper that you store the class name in. Then you need to use partial specialisation to get it to return the correct class name for you. This has the advantage of working compile time but is significantly more complex.

Edit: Being more explicit

template< typename Type > class ClassName
{
public:
    static std::string name()
    {
        return "Unknown";
    }
};

Then for each class somethign liek the following:

template<> class ClassName<MyClass>
{
public:
    static std::string name()
    {
        return "MyClass";
    }
};

Which could even be macro'd as follows:

#define DefineClassName( className ) \
\
template<> class ClassName<className> \
{ \
public: \
    static std::string name() \
    { \
        return #className; \
    } \
}; \

Allowing you to, simply, do

DefineClassName( MyClass );

Finally to Get the class name you'd do the following:

ClassName< MyClass >::name();

Edit2: Elaborating further you'd then need to put this "DefineClassName" macro in each class you make and define a "classname" function that would call the static template function.

Edit3: And thinking about it ... Its obviously bad posting first thing in the morning as you may as well just define a member function "classname()" as follows:

std::string classname()
{
     return "MyClass";
}

which can be macro'd as follows:

DefineClassName( className ) \
std::string classname()  \
{ \
     return #className; \
}

Then you can simply just drop

DefineClassName( MyClass );

into the class as you define it ...