How to compare two lists in python

Question

How to compare two lists in python   date    Thu Sep 16 13 14 15 CDT 2010   sdate    Thu Sep 16 14 14 15 CDT 2010   dateArr      dateArr   date split    sdateArr      sdateArr   sdate split      Now I want to compare these two lists  I guess split returns a list  We can do simple comparision in Java like dateArr i     sdateArr i   but how can we do it in Python

User · Answer

Given the code you provided in comments  I assume you want to do this    gt  gt  gt  dateList    Thu Sep 16 13 14 15 CDT 2010  split    gt  gt  gt  sdateList    Thu Sep 16 14 14 15 CDT 2010  split    gt  gt  gt  dateList    sdataList false   The split-method of the string returns a list  A list in Python is very different from an array     in this case does an element-wise comparison of the two lists and returns if all their elements are equal and the number and order of the elements is the same  Read the documentation

User · Answer

If you mean lists  try      l1    1 2 3  l2    1 2 3 4   l1    l2   False   If you mean array   l1   array  l    1  2  3   l2   array  d    1 0  2 0  3 0   l1    l2   True l2   array  d    1 0  2 0  3 0  4 0   l1    l2   False   If you want to compare strings  per your comment    date string    u Thu Sep 16 13 14 15 CDT 2010  date string2   u Thu Sep 16 14 14 15 CDT 2010  date string    date string2   False

User · Answer

From your post I gather that you want to compare dates  not arrays  If this is the case  then use the appropriate object  a datetime object   Please check the documentation for the datetime module  Dates are a tough cookie  Use reliable algorithms

User · Answer

You could always do just   a  1 2 3  b   a   b   c  1 2 3 4  d  1 2 3   a  b     returns False a  c     returns False a  d     returns True

User · Answer

a     a1   b2   c3   b     a1   b2   c3   c     b2   a1   c3      if you care about order a    b   True a    c   False    if you don t care about order AND duplicates set a     set b    True set a     set c    True  By casting a  b and c as a set  you remove duplicates and order doesn t count  Comparing sets is also much faster and more efficient than comparing lists

User · Answer

for i in arr1      if i in arr2          return 1     return  0 arr1  1 2 5  arr2  2 4 15  q checkarrayequalornot arr1 arr2  print q   gt  gt 0

[python] How to compare two lists in python?

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