[wpf] Get selected row item in DataGrid WPF

I have a DataGrid, bound to Database table, I need to get the content of selected row in DataGrid, for example, I want to show in MessageBox content of selected row.

Example of DataGrid:

So, if I select the second row, my MessageBox has to show something like: 646 Jim Biology.

private void Fetching_Record_Grid_MouseDoubleClick_1(object sender, MouseButtonEventArgs e)
{
    IInputElement element = e.MouseDevice.DirectlyOver;
    if (element != null && element is FrameworkElement)
    {
        if (((FrameworkElement)element).Parent is DataGridCell)
        {
            var grid = sender as DataGrid;
            if (grid != null && grid.SelectedItems != null && grid.SelectedItems.Count == 1)
            {
                //var rowView = grid.SelectedItem as DataRowView;
                try
                {
                    Station station = (Station)grid.SelectedItem;
                    id_txt.Text =  station.StationID.Trim() ;
                    description_txt.Text =  station.Description.Trim();
                }
                catch
                {

                }
            }
        }
    }
}

if I select the second row -

 Dim jason As DataRowView


    jason = dg1.SelectedItem

    noteText.Text = jason.Item(0).ToString()

noteText will be 646. This is VB, but you get it.

You can also:

DataRowView row = dataGrid.SelectedItem as DataRowView;
MessageBox.Show(row.Row.ItemArray[1].ToString());

@Krytox answer with MVVM

    <DataGrid 
        Grid.Column="1" 
        Grid.Row="1"
        Margin="10" Grid.RowSpan="2"
        ItemsSource="{Binding Data_Table}"
        SelectedItem="{Binding Select_Request, Mode=TwoWay}" SelectionChanged="DataGrid_SelectionChanged"/>//The binding



    #region View Model
    private DataRowView select_request;
    public DataRowView Select_Request
    {
        get { return select_request; }
        set
        {
            select_request = value;
            OnPropertyChanged("Select_Request"); //INotifyPropertyChange
            OnSelect_RequestChange();//do stuff
        }
     }

There are a lot of answers here that probably work in a specific context, but I was simply trying to get the text value of the first cell in a selected row. While the accepted answer here was the closest for me, it still required creating a type and casting the row into that type. I was looking for a simpler solution, and this is what I came up with:

MessageBox.Show(((DataRowView)DataGrid.SelectedItem).Row[0].ToString());

This gives me the first column in the selected row. Hopefully this helps someone else.

use your Model class to get row values selected from datagrid like,

        XDocument xmlDoc = XDocument.Load(filepath);

        if (tablet_DG.SelectedValue == null)
        {
            MessageBox.Show("select any record from list..!", "select atleast one record", MessageBoxButton.OKCancel, MessageBoxImage.Warning);
        }
        else
        {
            try
            {
                string tabletID = "";

                 /*here i have used my model class named as TabletMode*/

                var row_list = (TabletModel)tablet_DG.SelectedItem; 
                 tabletID= row_list.TabletID;

                var items = from item in xmlDoc.Descendants("Tablet")
                            where item.Element("TabletID").Value == tabletID
                            select item;

                foreach (var item in items)
                {
                    item.SetElementValue("Instance",row_list.Instance);
                    item.SetElementValue("Database",row_list.Database);
                }

                xmlDoc.Save(filepath);
                MessageBox.Show("Details Updated..!"
                + Environment.NewLine + "TabletId: " +row_list.TabletID + Environment.NewLine
                + "Instance:" + row_list.Instance + Environment.NewLine + "Database:" + row_list.Database, "", MessageBoxButton.YesNoCancel, MessageBoxImage.Information);
            }

            catch (Exception ex)
            {
                MessageBox.Show(ex.StackTrace);
            }
        }

Just discovered this one after i tried Fara's answer but it didn't work on my project. Just drag the column from the Data Sources window, and drop to the Label or TextBox.

This is pretty simple in this DataGrid dg and item class is populated in datagrid and listblock1 is a basic frame.

private void DataGrid_SelectionChanged(object sender, SelectionChangedEventArgs e)
    {
        try
        {
            var row_list = (Item)dg.SelectedItem;
            listblock1.Content = "You Selected: " + row_list.FirstName + " " + row_list.LastName;
        }
        catch { }

    }
    public class Item
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
    }

If you're using the MVVM pattern you can bind a SelectedRecord property of your VM with SelectedItem of the DataGrid, this way you always have the SelectedValue in you VM. Otherwise you should use the SelectedIndex property of the DataGrid.

Well I will put similar solution that is working fine for me.

 private void DataGrid1_SelectionChanged(object sender, SelectionChangedEventArgs e)
        {
            try
            {
                if (DataGrid1.SelectedItem != null)
                {
                    if (DataGrid1.SelectedItem is YouCustomClass)
                    {
                        var row = (YouCustomClass)DataGrid1.SelectedItem;

                        if (row != null)
                        {
                            // Do something...

                            //  ButtonSaveData.IsEnabled = true;

                            //  LabelName.Content = row.Name;

                        }
                    }
                }
            }
            catch (Exception)
            {
            }
        }

public IEnumerable<DataGridRow> GetDataGridRows(DataGrid grid)
{
    var itemsSource = grid.ItemsSource as IEnumerable;
    if (null == itemsSource) yield return null;
    foreach (var item in itemsSource)
    {
        var row = grid.ItemContainerGenerator.ContainerFromItem(item) as DataGridRow;
        if (null != row) yield return row;
    }
}

private void DataGrid_Details_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
    try
    {           
        var row_list = GetDataGridRows(DataGrid_Details);
        foreach (DataGridRow single_row in row_lis)
        {
            if (single_row.IsSelected == true)
            {
                MessageBox.Show("the row no."+single_row .GetIndex ().ToString ()+ " is selected!");
            }
        }

    }
    catch { }
}