I am getting the following C++ error:
array must be initialized with a brace enclosed initializer
From this line of C++
int cipher[Array_size][Array_size] = 0;
What is the problem here? What does the error mean? Below is the full code:
string decryption(string todecrypt)
{
int cipher[Array_size][Array_size] = 0;
string ciphercode = todecrypt.substr(0,3);
todecrypt.erase(0,3);
decodecipher(ciphercode,cipher);
string decrypted = "";
while(todecrypt.length()>0)
{
string unit_decrypt = todecrypt.substr(0,Array_size);
todecrypt.erase(0,Array_size);
int tomultiply[Array_size]=0;
for(int i = 0; i < Array_size; i++)
{
tomultiply[i] = int(unit_encrypt.substr(0,1));
unit_encrypt.erase(0,1);
}
for(int i = 0; i < Array_size; i++)
{
int resultchar = 0;
for(int j = 0; j<Array_size; j++)
{
resultchar += tomultiply[j]*cipher[i][j];
}
decrypted += char((resultchar%229)-26);
}
}
return decrypted;
}
This question is related to
c++
arrays
compiler-errors
You can't initialize arrays like this:
int cipher[Array_size][Array_size]=0;
The syntax for 2D arrays is:
int cipher[Array_size][Array_size]={{0}};
Note the curly braces on the right hand side of the initialization statement.
for 1D arrays:
int tomultiply[Array_size]={0};
You cannot initialize an array to '0' like that
int cipher[Array_size][Array_size]=0;
You can either initialize all the values in the array as you declare it like this:
// When using different values
int a[3] = {10,20,30};
// When using the same value for all members
int a[3] = {0};
// When using same value for all members in a 2D array
int a[Array_size][Array_size] = { { 0 } };
Or you need to initialize the values after declaration. If you want to initialize all values to 0 for example, you could do something like:
for (int i = 0; i < Array_size; i++ ) {
a[i] = 0;
}
Source: Stackoverflow.com