C error Array must be initialized with a brace enclosed initializer

Question

I am getting the following C   error   array must be initialized with a brace enclosed initializer    From this line of C    int cipher Array size  Array size    0    What is the problem here  What does the error mean  Below is the full code   string decryption string todecrypt        int cipher Array size  Array size    0      string ciphercode   todecrypt substr 0 3       todecrypt erase 0 3       decodecipher ciphercode cipher       string decrypted           while todecrypt length   gt 0                string unit decrypt   todecrypt substr 0 Array size           todecrypt erase 0 Array size           int tomultiply Array size  0          for int i   0  i  lt  Array size  i                          tomultiply i    int unit encrypt substr 0 1                unit encrypt erase 0 1                     for int i   0  i  lt  Array size  i                          int resultchar   0              for int j   0  j lt Array size  j                                  resultchar    tomultiply j  cipher i  j                              decrypted    char  resultchar 229 -26                       return decrypted

User · Answer

You cannot initialize an array to  0  like that  int cipher Array size  Array size  0    You can either initialize all the values in the array as you declare it like this      When using different values int a 3     10 20 30       When using the same value for all members int a 3     0       When using same value for all members in a 2D array int a Array size  Array size        0        Or you need to initialize the values after declaration  If you want to initialize all values to 0 for example  you could do something like   for  int i   0  i  lt  Array size  i           a i    0

User · Answer

You can t initialize arrays like this   int cipher Array size  Array size  0    The syntax for 2D arrays is   int cipher Array size  Array size    0      Note the curly braces on the right hand side of the initialization statement   for 1D arrays   int tomultiply Array size   0

User · Answer

The syntax to statically initialize an array uses curly braces  like this   int array 10      0      This will zero-initialize the array   For multi-dimensional arrays  you need nested curly braces  like this   int cipher Array size  Array size       0        Note that Array size must be a compile-time constant for this to work   If Array size is not known at compile-time  you must use dynamic initialization    Preferably  an std  vector

[c++] C++ error: "Array must be initialized with a brace enclosed initializer"

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