Convert an int to ASCII character

Question

I have   int i   6    and I want   char c    6    by conversion  Any simple way to suggest   EDIT  also i need to generate a random number  and convert to a char  then add a   txt  and access it in an ifstream

User · Answer

This is how I converted a number to an ASCII code. 0 though 9 in hex code is 0x30-0x39. 6 would be 0x36.

unsigned int temp = 6;
or you can use unsigned char temp = 6;
unsigned char num;
 num = 0x30| temp;

this will give you the ASCII value for 6. You do the same for 0 - 9

to convert ASCII to a numeric value I came up with this code.

unsigned char num,code;
code = 0x39; // ASCII Code for 9 in Hex
num = 0&0F & code;

User · Answer

Doing college work I gathered the data I found and gave me this result    The input consists of a single line with multiple integers  separated by a blank space  The end of the entry is identified by the number -1  which should not be processed     include  lt iostream gt   include  lt cstdlib gt   using namespace std   int main         char numeros 100     vetor para armazenar a entrada dos numeros a serem convertidos     int count   0  soma   0       cin getline numeros  100        system  cls       limpa a tela      for int i   0  i  lt  100  i                  if  numeros i      -      condicao de existencia do for             i   100          else                       if numeros i             condicao que ao encontrar um espaco manda o resultado dos dados lidos e zera a contagem                               if count    2     se contegem for 2 divide por 10 por nao ter casa da centena                     soma   soma   10                  if count    1     se contagem for 1 divide por 100 por nao ter casa da dezena                     soma   soma   100                    cout  lt  lt   char soma     saida das letras do codigo ascii                 count   0                             else                               count        contagem aumenta para saber se o numero esta na centena dezena ou unitaria                 if count    1                      soma      0  - numeros i     -100     a ideia    que o resultado de  0  -  x    -x  um numero inteiro                  if count    2                      soma   soma     0  - numeros i     -10     todos multiplicam por -1 para retornar um valor positivo                 if count    3                      soma   soma     0  - numeros i     -1     caso pense em entrada de valores na casa do milhar  deve-se alterar esses 3 if  s         alem de adicionar mais um para a casa do milhar                                        return 0      The comments are in Portuguese but I think you should understand  Any questions send me a message on linkedin  https   www linkedin com in marcosfreitasds

User · Answer

I suppose that  std  to string i    could do the job  it s an overloaded function  it could be any numeric type such as int  double or float

User · Answer

This will only work for int-digits 0-9  but your question seems to suggest that might be enough   It works by adding the ASCII value of char  0  to the integer digit   int i 6  char c    0  i      now c is  6    For example    0  0    0   0  1    1   0  2    2   0  3    3    Edit   It is unclear what you mean   work for alphabets   If you want the 5th letter of the alphabet   int i 5  char c    A -1   i     c is now  E   the 5th letter    Note that because in C Ascii  A is considered the 0th letter of the alphabet  I do a minus-1 to compensate for the normally understood meaning of 5th letter   Adjust as appropriate for your specific situation  and test-test-test  any code you write

User · Answer

itoa    http   www cplusplus com reference clibrary cstdlib itoa

User · Answer

I have int i   6  and I want char c    6  by conversion  Any simple way to suggest    There are only 10 numbers   So write a function that takes an int from 0-9 and returns the ascii code   Just look it up in an ascii table and write a function with ifs or a select case

User · Answer

My way to do this job is  char to int char var  cout lt  lt  int var-48       int to char int var  cout lt  lt  char  var 48    And I write these functions for conversions  int char2int char  szBroj       int counter 0      int results 0      while 1           if szBroj counter     0                break           else              results  10              results   int szBroj counter -48              counter                        return results     char   int2char int iNumber       int iNumbersCount 0      int iTmpNum iNumber      while iTmpNum           iTmpNum  10          iNumbersCount              char  buffer new char iNumbersCount 1       for int i iNumbersCount-1 i gt  0 i--           buffer i   char   iNumber 10  48           iNumber  10            buffer iNumbersCount    0       return buffer

User · Answer

Alternative way  But non-standard   int i   6  char c 2   char  str   NULL  if   itoa s i  c  2  10     0     str   c    Or Using standard c   stringstream   std  ostringstream oss   oss  lt  lt  6

User · Answer

Straightforward way   char digits       0    1    2    3    4    5    6    7    8    9     char aChar   digits i     Safer way   char aChar    0    i    Generic way   itoa i         Handy way    sprintf myString    d   i    C   way   taken from Dave18 answer   std  ostringstream oss  oss  lt  lt  6    Boss way      Joe  write me an int to char converter   Studboss way      char aChar    6     Joe s way      char aChar    6     int i   6    Nasa s way        Waiting for reply from satellite      Alien s way   9        Greetings    God s way      Bruh I built this   Peter Pan s way   char aChar   switch  i      case 0      aChar    0       break    case 1      aChar    1       break    case 2      aChar    2       break    case 3      aChar    3       break    case 4      aChar    4       break    case 5      aChar    5       break    case 6      aChar    6       break    case 7      aChar    7       break    case 8      aChar    8       break    case 9      aChar    9       break    default      aChar            break      Santa Claus s way     Wait till Christmas  sleep 457347347     Gravity s way        What    6   Jersey  Mikes     way           SO way      Guys  how do I avoid reading   beginner s guide to C      My way      or the highway    Comment  I ve added Handy way and C   way  to have a complete collection  and I m saving this as a wiki    Edit  satisfied

User · Answer

Just FYI  if you want more than single digit numbers you can use sprintf   char txt 16   int myNum   20  sprintf txt    d   myNum     Then the first digit is in a char at txt 0   and so on    This is the C approach  not the C   approach  The C   way would be to use stringstreams

User · Answer

A PROGRAM TO CONVERT INT INTO ASCII                 include lt stdio h gt             include lt string h gt             include lt conio h gt              char data 1000                      thing in the bracket is optional              char data1 1000                    int val  a             char varray  9               void binary  int digit                            if digit  0                 val 48                if digit  1                 val 49                if digit  2                 val 50                if digit  3                 val 51                if digit  4                 val 52                if digit  5                 val 53                if digit  6                 val 54                if digit  7                 val 55                if digit  8                 val 56                if digit  9                  val 57                  a 0              while val  0                             if val 2  0                                   varray a    0                                    else                varray a   1                  val val 2                 a                              while a  7                          varray a   0               a                             varray  8    NULL            strrev  varray             strcpy  data1 varray             strcat  data1 data             strcpy  data data1                           void main                         int num             clrscr               printf  enter number n               scanf   d   amp num              if num  0             binary 0              else            while num gt 0                          binary num 10              num num 10                          puts data              getch                    I check my coding and its working good let me know if its helpful thanks

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