module Enumerable
def map_with_index(&block)
i = 0
self.map { |val|
val = block.call(val, i)
i += 1
val
}
end
end
["foo", "bar"].map_with_index {|item, index| [item, index] } => [["foo", 0], ["bar", 1]]
A fun, but useless way to do this:
az = ('a'..'z').to_a
azz = az.map{|e| [e, az.index(e)+2]}
I often do this:
arr = ["a", "b", "c"]
(0...arr.length).map do |int|
[arr[int], int + 2]
end
#=> [["a", 2], ["b", 3], ["c", 4]]
Instead of directly iterating over the elements of the array, you're iterating over a range of integers and using them as the indices to retrieve the elements of the array.
Over the top obfuscation:
arr = ('a'..'g').to_a
indexes = arr.each_index.map(&2.method(:+))
arr.zip(indexes)
Ruby has Enumerator#with_index(offset = 0), so first convert the array to an enumerator using Object#to_enum or Array#map:
[:a, :b, :c].map.with_index(2).to_a
#=> [[:a, 2], [:b, 3], [:c, 4]]
a = [1, 2, 3]
p [a, (2...a.size+2).to_a].transpose
In ruby 1.9.3 there is a chainable method called with_index
which can be chained to map.
For example:
array.map.with_index { |item, index| ... }
I have always enjoyed the syntax of this style:
a = [1, 2, 3, 4]
a.each_with_index.map { |el, index| el + index }
# => [1, 3, 5, 7]
Invoking each_with_index
gets you an enumerator you can easily map over with your index available.
Here are two more options for 1.8.6 (or 1.9) without using enumerator:
# Fun with functional
arr = ('a'..'g').to_a
arr.zip( (2..(arr.length+2)).to_a )
#=> [["a", 2], ["b", 3], ["c", 4], ["d", 5], ["e", 6], ["f", 7], ["g", 8]]
# The simplest
n = 1
arr.map{ |c| [c, n+=1 ] }
#=> [["a", 2], ["b", 3], ["c", 4], ["d", 5], ["e", 6], ["f", 7], ["g", 8]]
Source: Stackoverflow.com