[python] how to output every line in a file python

     if data.find('!masters') != -1:
         f = open('masters.txt')
         lines = f.readline()
         for line in lines:
               print lines
               sck.send('PRIVMSG ' + chan + " " + str(lines) + '\r\n')
               f.close()

masters.txt has a list of nicknames, how can I print every line from the file at once?. The code I have only prints the first nickname. Your help will be appreciate it. Thanks.

You probably want something like:

if data.find('!masters') != -1:
     f = open('masters.txt')
     lines = f.read().splitlines()
     f.close()
     for line in lines:
         print line
         sck.send('PRIVMSG ' + chan + " " + str(line) + '\r\n')

Don't close it every iteration of the loop and print line instead of lines. Also use readlines to get all the lines.

EDIT removed my other answer - the other one in this discussion is a better alternative than what I had, so there's no reason to copy it.

Also stripped off the \n with read().splitlines()

Loop through the file.

f = open("masters.txt")
lines = f.readlines()
for line in lines:
    print line

Did you try

for line in open("masters", "r").readlines(): print line

?

readline() 

only reads "a line", on the other hand

readlines()

reads whole lines and gives you a list of all lines.

You could try this. It doesn't read all of f into memory at once (using the file object's iterator) and it closes the file when the code leaves the with block.

if data.find('!masters') != -1:
    with open('masters.txt', 'r') as f:
        for line in f:
            print line
            sck.send('PRIVMSG ' + chan + " " + line + '\r\n')

If you're using an older version of python (pre 2.6) you'll have to have

from __future__ import with_statement