I wanted to declare a 2D array and assign values to it, without running a for loop.
I thought I could used the following idea
int array[5] = {1,2,3,4,5};
Which works fine to initialize the 2D array as well. But apparently my compiler doesn't like this.
/*
1 8 12 20 25
5 9 13 24 26
*/
#include <iostream.h>
int main()
{
int arr[2][5] = {0}; // This actually initializes everything to 0.
arr [1] [] = {1,8,12,20,25}; // Line 11
arr [2] [] = {5,9,13,24,26};
return 0;
}
J:\CPP\Grid>bcc32.exe Grid.cpp
Borland C++ 5.5.1 for Win32 Copyright (c) 1993, 2000 Borland
Grid.cpp:
Error E2188 Grid.cpp 11: Expression syntax in function main()
Error E2188 Grid.cpp 12: Expression syntax in function main()
Warning W8004 Grid.cpp 14: 'arr' is assigned a value that is never used in funct ion main()
* 2 errors in Compile *
Please help as to what is the right way to initialize the 2d array with my set of values.
This question is related to
c++
c
multidimensional-array
initialization
shortcut
Like this:
int main()
{
int arr[2][5] =
{
{1,8,12,20,25},
{5,9,13,24,26}
};
}
This should be covered by your C++ textbook: which one are you using?
Anyway, better, consider using std::vector or some ready-made matrix class e.g. from Boost.
One alternative is to represent your 2D array as a 1D array. This can make element-wise operations more efficient. You should probably wrap it in a class that would also contain width and height.
Another alternative is to represent a 2D array as an std::vector<std::vector<int> >. This will let you use STL's algorithms for array arithmetic, and the vector will also take care of memory management for you.
The proper way to initialize a multidimensional array in C or C++ is
int arr[2][5] = {{1,8,12,20,25}, {5,9,13,24,26}};
You can use this same trick to initialize even higher-dimensional arrays if you want.
Also, be careful in your initial code - you were trying to use 1-indexed offsets into the array to initialize it. This didn't compile, but if it did it would cause problems because C arrays are 0-indexed!
Just want to point out you do not need to specify all dimensions of the array.
The leftmost dimension can be 'guessed' by the compiler.
#include <stdio.h>
int main(void) {
int arr[][5] = {{1,2,3,4,5}, {5,6,7,8,9}, {6,5,4,3,2}};
printf("sizeof arr is %d bytes\n", (int)sizeof arr);
printf("number of elements: %d\n", (int)(sizeof arr/sizeof arr[0]));
return 0;
}
int iArray[2][2] = {{1, 2}, {3, 4}};
Think of a 2D array as an array of arrays.
Source: Stackoverflow.com