Retrieving parameters from a URL

Question

Given a URL like the following  how can I parse the value of the query parameters  For example  in this case I want the value of def    abc def  ghi    I am using Django in my environment  is there a method on the request object that could help me   I tried using self request get  def   but it is not returning the value ghi as I had hoped

User · Answer

for Python   3 4  from urllib import parse url    http   foo appspot com abc def ghi  query def parse parse qs parse urlparse url  query   def   0

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I know this is a bit late but since I found myself on here today  I thought that this might be a useful answer for others   import urlparse url    http   example com  q abc amp p 123  parsed   urlparse urlparse url  params   urlparse parse qsl parsed query  for x y in params      print  Parameter     x  Value     y   With parse qsl     Data are returned as a list of name  value pairs

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The urlparse module provides everything you need   urlparse parse qs

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Python 2   import urlparse url    http   foo appspot com abc def ghi  parsed   urlparse urlparse url  print urlparse parse qs parsed query   def     Python 3   import urllib parse as urlparse from urllib parse import parse qs url    http   foo appspot com abc def ghi  parsed   urlparse urlparse url  print parse qs parsed query   def      parse qs returns a list of values  so the above code will print   ghi     Here s the Python 3 documentation

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I didn t want to mess with additional libraries  Simple ways suggested here didn t work out either  Finally  not on the request object  but I could get a GET parameter w o all that hassle via self GET get  XXX        def get context data self    kwargs       context   super SomeView  self  get context data   kwargs      context  XXX     self GET get  XXX        Python 2 7 18  Django 1 11 20

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parameters   dict  part split      for part in   get parsed url 4  split   amp        This one is simple  The variable parameters will contain a dictionary of all the parameters

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def getParams url       params   url split      1      params   params split          pairs   zip params 0  2   params 1  2       answer   dict  k v  for k v in pairs    Hope this helps

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Most answers here suggest using parse qs to parse an URL string  This method always returns the values as a list  not directly as a string  because a parameter can appear multiple times  e g   http   example com  foo bar amp foo baz amp bar baz Would return    foo     bar    baz     bar      baz    This is a bit inconvenient because in most cases you re dealing with an URL that doesn t have the same parameter multiple times  This function returns the first value by default  and only returns a list if there s more than one element  from urllib import parse  def parse urlargs url       query   parse parse qs parse urlparse url  query      return  k v 0  if v and len v     1 else v for k v in query items     For example  http   example com  foo bar amp foo baz amp bar baz would return    foo     bar    baz     bar    baz

User · Answer

There s not need to do any of that  Only with  self request get  variable name     Notice that I m not specifying the method  GET  POST  etc   This is well documented and this is an example  The fact that you use Django templates doesn t mean the handler is processed by Django as well

User · Answer

There is a nice library w3lib url  from w3lib url import url query parameter url     abc def ghi  print url query parameter url   def   ghi

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import urlparse url    http   example com  q abc amp p 123  par   urlparse parse qs urlparse urlparse url  query   print par  q   0   par  p   0

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import cgitb cgitb enable    import cgi print  Content-Type  text plain charset utf-8  print form   cgi FieldStorage   i   int form getvalue  a    int form getvalue  b    print i

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Btw  I was having issues using parse qs   and getting empty value parameters and learned that you have to pass a second optional parameter  keep blank values  to return a list of the parameters in a query string that contain no values  It defaults to false  Some crappy written APIs require parameters to be present even if they contain no values  for k v in urlparse parse qs p query  True  items      print k

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In pure Python   def get param from url url  param name       return  i split      -1  for i in url split      1  -1  split   amp    if i startswith param name         0

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There is a new library called furl  I find this library to be most pythonic for doing url algebra   To install   pip install furl   Code   from furl import furl f   furl   abc def  ghi     print f args  def

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The url you are referring is a query type and I see that the request object supports a method called arguments to get the query arguments  You may also want try self request get  def   directly to get your value from the object

User · Answer

I m shocked this solution isn t on here already  Use    request GET get  variable name     This will  get  the variable from the  GET  dictionary  and return the  variable name  value if it exists  or a None object if it doesn t exist

User · Answer

I see there isn t an answer for users of Tornado   key   self request query arguments get  key   None    This method must work inside an handler that is derived from    tornado web RequestHandler   None is the answer this method will return when the requested key can t be found  This saves you some exception handling

[python] Retrieving parameters from a URL

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