I want to get the current time of my system. For that I'm using the following code in C:
time_t now;
struct tm *mytime = localtime(&now);
if ( strftime(buffer, sizeof buffer, "%X", mytime) )
{
printf("time1 = \"%s\"\n", buffer);
}
The problem is that this code is giving some random time. Also, the random time is different everytime. I want the current time of my system.
LONG VERSION
src: https://en.wikipedia.org/wiki/C_date_and_time_functions
#include <time.h>
#include <stdlib.h>
#include <stdio.h>
int main(void)
{
time_t current_time;
char* c_time_string;
/* Obtain current time. */
current_time = time(NULL);
if (current_time == ((time_t)-1))
{
(void) fprintf(stderr, "Failure to obtain the current time.\n");
exit(EXIT_FAILURE);
}
/* Convert to local time format. */
c_time_string = ctime(¤t_time);
if (c_time_string == NULL)
{
(void) fprintf(stderr, "Failure to convert the current time.\n");
exit(EXIT_FAILURE);
}
/* Print to stdout. ctime() has already added a terminating newline character. */
(void) printf("Current time is %s", c_time_string);
exit(EXIT_SUCCESS);
}
The output is:
Current time is Thu Sep 15 21:18:23 2016
SHORT VERSION:
#include <stdio.h>
#include <time.h>
int main(int argc, char *argv[]) {
time_t current_time;
time(¤t_time);
printf("%s", ctime(¤t_time));
The output is:
Current time is Thu Jan 28 15:22:31 2021
#include <stdio.h>
#include <time.h>
void main()
{
time_t t;
time(&t);
clrscr();
printf("Today's date and time : %s",ctime(&t));
getch();
}
guys i got a new way get system time. though its lengthy and is full of silly works but in this way you can get system time in integer format.
#include <stdio.h>
#include <stdlib.h>
int main()
{
FILE *fp;
char hc1,hc2,mc1,mc2;
int hi1,hi2,mi1,mi2,hour,minute;
system("echo %time% >time.txt");
fp=fopen("time.txt","r");
if(fp==NULL)
exit(1) ;
hc1=fgetc(fp);
hc2=fgetc(fp);
fgetc(fp);
mc1=fgetc(fp);
mc2=fgetc(fp);
fclose(fp);
remove("time.txt");
hi1=hc1;
hi2=hc2;
mi1=mc1;
mi2=mc2;
hi1-=48;
hi2-=48;
mi1-=48;
mi2-=48;
hour=hi1*10+hi2;
minute=mi1*10+mi2;
printf("Current time is %d:%d\n",hour,minute);
return 0;
}
Easy way:
#include <time.h>
#include <stdio.h>
#include <string.h>
int main(void)
{
time_t mytime = time(NULL);
char * time_str = ctime(&mytime);
time_str[strlen(time_str)-1] = '\0';
printf("Current Time : %s\n", time_str);
return 0;
}
#include<stdio.h>
#include<time.h>
void main()
{
time_t t;
time(&t);
printf("\n current time is : %s",ctime(&t));
}
If you just need the time without the date.
time_t rawtime;
struct tm * timeinfo;
time( &rawtime );
timeinfo = localtime( &rawtime );
printf("%02d:%02d:%02d", timeinfo->tm_hour, timeinfo->tm_min,
timeinfo->tm_sec);
You can use this function to get current local time. if you want gmt then use the gmtime
function instead of localtime
. cheers
time_t my_time;
struct tm * timeinfo;
time (&my_time);
timeinfo = localtime (&my_time);
CCLog("year->%d",timeinfo->tm_year+1900);
CCLog("month->%d",timeinfo->tm_mon+1);
CCLog("date->%d",timeinfo->tm_mday);
CCLog("hour->%d",timeinfo->tm_hour);
CCLog("minutes->%d",timeinfo->tm_min);
CCLog("seconds->%d",timeinfo->tm_sec);
Initialize your now
variable.
time_t now = time(0); // Get the system time
The localtime
function is used to convert the time value in the passed time_t
to a struct tm
, it doesn't actually retrieve the system time.
To extend the answer from @mingos above, I wrote the below function to format my time to a specific format ([dd mm yyyy hh:mm:ss]).
// Store the formatted string of time in the output
void format_time(char *output){
time_t rawtime;
struct tm * timeinfo;
time ( &rawtime );
timeinfo = localtime ( &rawtime );
sprintf(output, "[%d %d %d %d:%d:%d]",timeinfo->tm_mday, timeinfo->tm_mon + 1, timeinfo->tm_year + 1900, timeinfo->tm_hour, timeinfo->tm_min, timeinfo->tm_sec);
}
More information about struct tm
can be found here.
Source: Stackoverflow.com