Regex to validate password strength

Question

My password strength criteria is as below      8 characters length 2 letters in Upper Case 1 Special Character       amp    2 numerals  0-9  3 letters in Lower Case   Can somebody please give me regex for same  All conditions must be met by password

User · Answer

Another solution   import re  passwordRegex   re compile r                A-Z    A-Z                    at least two capital letters                amp                           at least one of these special c-er           0-9    0-9                     at least two numeric digits           a-z    a-z    a-z              at least three lower case letters       8                                  at least 8 total digits                 re VERBOSE   def userInputPasswordCheck        print  Enter a potential password        while True          m   input           mo   passwordRegex search m           if  not mo              print     Your password should have at least one special charachter  two digits  two uppercase and three lowercase charachter  Length  8  ch-ers   Enter another password                        else             print  Password is strong              return userInputPasswordCheck

User · Answer

Password must meet at least 3 out of the following 4 complexity rules    at least 1 uppercase character  A-Z   at least 1 lowercase character  a-z   at least 1 digit  0-9   at least 1 special character     do not forget to treat space as special characters too   at least 10 characters   at most 128 characters   not more than 2 identical characters in a row  e g   111 not allowed              1 2         a-z       A-Z       0-9        a-z       A-Z        a-zA-Z0-9        A-Z       0-9        a-zA-Z0-9        a-z       0-9         a-zA-Z0-9     10 127              1 2         a-z       A-Z        0-9         a-z       A-Z         a-zA-Z0-9         A-Z       0-9         a-zA-Z0-9         a-z       0-9         a-zA-Z0-9      10 127

User · Answer

For PHP  this works fine    if preg match            A-Z   A-Z   2          0-9   0-9   2    8          CaSu4Li8         return true    else      return fasle       in this case the result is true  Thsks for  ridgerunner

User · Answer

You should also consider changing some of your rules to   Add more special characters i e              -        and period  I m adding all the special characters that you missed above the number signs in US keyboards  Escape the ones regex uses  Make the password 8 or more characters  Not just a static number 8   With the above improvements  and for more flexibility and readability  I would modify the regex to          a-z   3          A-Z   2          0-9   2                 amp     -       1     8     Basic Explanation       RULE  MIN OCCURANCES          Each rule block is shown by           The rule and number of occurrences can then be easily specified and tested separately  before getting combined Detailed Explanation                                 start anchor        a-z   3                  lowercase letters   3   indicates that you want 3 of this group        A-Z   2                  uppercase letters   2   indicates that you want 2 of this group        0-9   2                  numbers   2   indicates that you want 2 of this group               amp     -       1     all the special characters in the    fields  The ones used by regex are escaped by using the   or the character itself   1   is redundant  but good practice  in case you change that to more than 1 in the future  Also keeps all the groups consistent  8                              indicates that you want 8 or more                                 end anchor  And lastly  for testing purposes here is a robulink with the above regex

User · Answer

You can use zero-length positive look-aheads to specify each of your constraints separately        8         p Lu    p Lu             amp          0-9        p Ll    p Ll     If your regex engine doesn t support the  p notation and pure ASCII is enough  then you can replace  p Lu  with  A-Z  and  p Ll  with  a-z

User · Answer

import re  RegexLength re compile r   S 8      RegexDigit re compile r  d   RegexLower re compile r  a-z    RegexUpper re compile r  A-Z      def IsStrongPW password       if RegexLength search password     None or RegexDigit search password     None or RegexUpper search password     None or RegexLower search password     None          return False     else          return True  while True      userpw input  please input your passord to check   n       if userpw     exit           break     else          print IsStrongPW userpw

User · Answer

You can do these checks using positive look ahead assertions            A-Z    A-Z             amp          0-9    0-9        a-z    a-z    a-z    8     Rubular link  Explanation                             Start anchor       A-Z    A-Z          Ensure string has two uppercase letters             amp                Ensure string has one special case letter        0-9    0-9          Ensure string has two digits        a-z    a-z    a-z   Ensure string has three lowercase letters    8                       Ensure string is of length 8                            End anchor

User · Answer

Answers given above are perfect but I suggest to use multiple smaller regex rather than a big one  Splitting the long regex have some advantages       easiness to write and read    easiness to debug easiness to add remove part of regex   Generally this approach keep code easily maintainable   Having said that  I share a piece of code that I write in Swift as example   struct RegExp                 Check password complexity       - parameter password          password to test      - parameter length            password min length      - parameter patternsToEscape  patterns that password must not contains      - parameter caseSensitivty    specify if password must conforms case sensitivity or not      - parameter numericDigits     specify if password must conforms contains numeric digits or not       - returns  boolean that describes if password is valid or not             static func checkPasswordComplexity password password  String  length  Int  patternsToEscape   String   caseSensitivty  Bool  numericDigits  Bool  - gt  Bool           if  password length  lt  length                return false                   if caseSensitivty               let hasUpperCase   RegExp matchesForRegexInText   A-Z    text  password  count  gt  0             if  hasUpperCase                   return false                           let hasLowerCase   RegExp matchesForRegexInText   a-z    text  password  count  gt  0             if  hasLowerCase                   return false                                 if numericDigits               let hasNumbers   RegExp matchesForRegexInText    d   text  password  count  gt  0             if  hasNumbers                   return false                                 if patternsToEscape count  gt  0               let passwordLowerCase   password lowercaseString             for pattern in patternsToEscape                   let hasMatchesWithPattern   RegExp matchesForRegexInText pattern  text  passwordLowerCase  count  gt  0                 if hasMatchesWithPattern                       return false                                                   return true            static func matchesForRegexInText regex  String  text  String  - gt   String            do               let regex   try NSRegularExpression pattern  regex  options                  let nsString   text as NSString             let results   regex matchesInString text                  options      range  NSMakeRange 0  nsString length               return results map   nsString substringWithRange  0 range             catch let error as NSError               print  invalid regex    error localizedDescription                return

User · Answer

codaddict s solution works fine  but this one is a bit more efficient   Python syntax   password   re compile r       py password Rev 20160831 2100        Validate password  2 upper  1 special  2 digit  1 lower  8 chars                                 Anchor to start of string              A-Z   A-Z   2      At least two uppercase                amp          amp         At least one  special               0-9   0-9   2      At least two digit        8                        Password length is 8 or more                                 Anchor to end of string           re VERBOSE    The negated character classes consume everything up to the desired character in a single step  requiring zero backtracking   The dot star solution works just fine   but does require some backtracking   Of course with short target strings such as passwords  this efficiency improvement will be negligible

User · Answer

I would suggest adding       pass   word   1234   qwer   asdf  exclude common passwords

User · Answer

All of above regex unfortunately didn t worked for me  A strong password s basic rules are   Should contain at least a capital letter Should contain at least a small letter Should contain at least a number Should contain at least a special character And minimum length   So  Best Regex would be         a-z        A-Z        0-9                 amp       8      The above regex have minimum length of 8  You can change it from  8   to  any number    Modification in rules   let  say you want minimum x characters small letters  y characters capital letters  z characters numbers  Total minimum length w  Then try below regex         a-z  x         A-Z  y         0-9  z                  amp       w      Note  Change x  y  z  w in regex  Edit  Updated regex answer  Edit2  Added modification

[regex] Regex to validate password strength

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