How to print variable addresses in C

Question

When i run this code     include  lt stdio h gt   void moo int a  int  b    int main         int x      int  y       x   1      y    amp x       printf  Address of x    d  value of x    d n    amp x  x       printf  Address of y    amp d  value of y    d  value of  y    d n    amp y  y   y       moo 9  y      void moo int a  int  b        printf  Address of a    d  value of a    d n    amp a  a       printf  Address of b    d  value of b    d  value of  b    d n    amp b  b   b       I keep getting this error in my compiler    Volumes MY USB C Programming Practice addresses c 16  warning  format     d    expects type    int     but argument 2 has type    int       Volumes MY USB C Programming Practice addresses c 17  warning  format     d    expects type    int     but argument 2 has type    int        Volumes MY USB C Programming Practice addresses c 17  warning  format     d    expects type    int     but argument 3 has type    int       Volumes MY USB C Programming Practice addresses c  In function    moo      Volumes MY USB C Programming Practice addresses c 23  warning  format     d    expects type    int     but argument 2 has type    int       Volumes MY USB C Programming Practice addresses c 24  warning  format     d    expects type    int     but argument 2 has type    int        Volumes MY USB C Programming Practice addresses c 24  warning  format     d    expects type    int     but argument 3 has type    int        Could you help me   Thanks  blargman

User · Answer

To print the address of a variable  you need to use the  p format   d is for signed integers  For example    include lt stdio h gt   void main void      int a     printf  Address is  p    amp a

User · Answer

I tried in online compiler  https   www onlinegdb com online c   compiler  int main         cout lt  lt  Hello World       int x   10      int  p    amp x      printf   nAddress of x is  p n    amp x      0x7ffc7df0ea54     printf  Address of p is  p n   p         0x7ffc7df0ea54      return 0

User · Answer

You want to use  p to print a pointer   From the spec      p  The argument shall be a pointer to void  The value of the pointer is converted to a sequence of printing characters  in an implementation-defined manner    And don t forget the cast  e g   printf   p n   void   amp a

User · Answer

When you intend to print the memory address of any variable or a pointer  using  d won t do the job and will cause some compilation errors  because you re trying to print out a number instead of an address  and even if it does work  you d have an intent error  because a memory address is not a number  the value 0xbfc0d878 is surely not a number  but an address   What you should use is  p  e g     include lt stdio h gt   int main void         int a      a   5      printf  The memory address of a is   p n    void    amp a       return 0      Good luck

User · Answer

Looks like you use  p  Print Pointers

[c] How to print variable addresses in C?

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