this is my code:
print str(float(1/3))+'%'
and it shows:
0.0%
but I want to get 33%
What can I do?
This question is related to
python
python-2.x
You are dividing integers then converting to float. Divide by floats instead.
As a bonus, use the awesome string formatting methods described here: http://docs.python.org/library/string.html#format-specification-mini-language
To specify a percent conversion and precision.
>>> float(1) / float(3)
[Out] 0.33333333333333331
>>> 1.0/3.0
[Out] 0.33333333333333331
>>> '{0:.0%}'.format(1.0/3.0) # use string formatting to specify precision
[Out] '33%'
>>> '{percent:.2%}'.format(percent=1.0/3.0)
[Out] '33.33%'
A great gem!
Then you'd want to do this instead:
print str(int(1.0/3.0*100))+'%'
The .0
denotes them as floats and int()
rounds them to integers afterwards again.
Just to add Python 3 f-string solution
prob = 1.0/3.0
print(f"{prob:.0%}")
There is a way more convenient 'percent'-formatting option for the .format()
format method:
>>> '{:.1%}'.format(1/3.0)
'33.3%'
Just for the sake of completeness, since I noticed no one suggested this simple approach:
>>> print("%.0f%%" % (100 * 1.0/3))
33%
Details:
%.0f
stands for "print a float with 0 decimal places", so %.2f
would print 33.33
%%
prints a literal %
. A bit cleaner than your original +'%'
1.0
instead of 1
takes care of coercing the division to float, so no more 0.0
Source: Stackoverflow.com