[c] error: invalid type argument of ‘unary *’ (have ‘int’)

Once you declare the type of a variable, you don't need to cast it to that same type. So you can write a=&b;. Finally, you declared c incorrectly. Since you assign it to be the address of a, where a is a pointer to int, you must declare it to be a pointer to a pointer to int.

#include <stdio.h>
int main(void)
{
    int b=10;
    int *a=&b;
    int **c=&a;
    printf("%d", **c);
    return 0;
}